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g100num [7]
3 years ago
5

The smallest separation resolvable by a microscope is of the order of magnitude of the wavelength used. What energy electrons wo

uld one need in an electron microscope to resolve separations of
(a) 150 Angstrom

(b) 5 Angstrom
Physics
1 answer:
hjlf3 years ago
6 0

Answer: a) for 150 Angstroms 6.63 *10^-3 eV; b) for 5 Angstroms 6.02 eV

Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

Finally we have:

eΔV=p^2/2m= h^2/(2*m*λ^2)

replacing we obtained the above values.

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