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Mademuasel [1]
3 years ago
7

In the classic 1960s science-fiction comic book The Atom, a physicist discovers a basketball-sized meteorite (about 12 cm in rad

ius) that is actually a fragment of a white dwarf star. With some difficulty he manages to hand-carry the meteorite back to his laboratory.
Estimate the mass of such a fragment.
Physics
1 answer:
kirill [66]3 years ago
7 0
This app is broken but
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Un coche de carreras de Fórmula 1 (véase Figura 2.30) acelera desde el reposo a razón de 18 m.s-2 . Suma que se mueve en línea r
Lynna [10]

Answer:

I will answer in English.

Ok, we know that the acceleration is a = 18m/s^2, and we have that the initial velocity and position are both zero. (because it starts at rest)

then we have:

a(t) = 18m/s^2

for the velocity, we integrate over time (because the initial velocity is equal to zero we do not have any integration constant)

v(t) = (18m/s^2)*t

for the position we integrate again over time, and again, we do not have any integration constant

p(t) = (1/2)(18m/s^2)*t^2 = (9m/s^2)*t^2

a) The speed at t= 3s can be found by replacing t = 3s in the velocity equation.

v(3s) =  (18m/s^2)*3s = 54m/s

b) the distance traveled by this time can be found by replacing t = 3s in the position equation.

p(3s) =(9m/s^2)*(3s)^2 = 81 m

c) first, we need to find what is the time when the position is equal to 200m.

p(t) = 200m =  (9m/s^2)*t^2

√(200/9) s = t = 4.7s

Now we replace that time in the velocity equation and we get:

v (4.7s) =   (18m/s^2)*4.7s = 84.6m/s

d) ok, to do this we know that.

1 hour has: 60*60 = 3600 seconds.

then we have the transformation  k = 1h/3600s

1 km has 1000 meters.

then we have the transformation c = 1km/1000m

so we have that:

84.6m/s = 84.6m/s*(c/k) = 84.6*(3600/1000)km/h = 304.56 km/h

6 0
3 years ago
Water soaks down into the ground in a process known as
astraxan [27]

I think the answer is D

3 0
4 years ago
Read 2 more answers
The block accelerates down the 30 degree incline at 3m/s2. What is the coefficient of friction of these surfaces
dolphi86 [110]
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
8 0
3 years ago
If the length of a building is 2 1 2 times the width and each dimension is increased by 7 ft, then the perimeter is 266 ft. Find
N76 [4]

Answer:

The original dimensions of the building is 95 ft × 38 ft.

Explanation:

Let the original length be 'l' and original width be 'w'.

Given:

Original length (l) = 2\frac{1}{2}\times original\ width

Original width = 'w'.

So, l=2\frac{1}{2}w=\frac{5}{2}w

Now, as per question:

Length and width is increased by 7 ft.

So, new length (l') = l+7=\frac{5w}{2}+7

New width (w') = w+7

New perimeter (P) = 266 ft

Perimeter is given as:

P=2(l' +w')\\\\266=2(\frac{5w}{2}+w)\\\\\frac{266}{2}=\frac{5w+2w}{2}\\\\266=7w\\\\w=\frac{266}{7}=38\ ft

Therefore, original width = 38 ft.

Original length is, l=\frac{5\times 38}{2}=\frac{190}{2}=95\ ft

Hence, the original dimensions of the building is 95 ft × 38 ft.

7 0
4 years ago
When the voltage
ValentinkaMS [17]
The current will increase at the same rate the voltage does.
6 0
3 years ago
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