If 50 milliliters (mL) of a 0.01 M HCl solution is required to neutralize exactly 25 milliliters (mL) of NaOH, what is the conce

Question

adoni [48]

4 years ago

12

If 50 milliliters (mL) of a 0.01 M HCl solution is required to neutralize exactly 25 milliliters (mL) of NaOH, what is the conce

ntration of the base?
A. 0.01m
B. 0.02m
C. 0.0005m
D. 0.04m

Chemistry

1 answer:

Sindrei [870] · Answer 1 · 2021-12-03T15:18:38+03:00

Sindrei [870]4 years ago

4 0

NaOH + HCl ----> NaCl + H2O

From reaction number of mole NaOH should be equal number of mole HCl.
n=MV
n- number of mole,
M - molarity,
V- volume.
M(NaOH)*V(NaOH) = M(HCl)*V(HCl)
M(NaOH)*25 ml = 0.01M*50 ml
V(NaOH) = 0.01*50/25=0.02 M
Answer B. 0.02 M