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makkiz [27]
3 years ago
15

0.005 kg = how many dg ?

Chemistry
2 answers:
Ymorist [56]3 years ago
8 0
0.005 kg = 50 dg
Hope this helps
muminat3 years ago
7 0

Answer:

There are 50 decigrams in 0.005 kilo grams.

Explanation:

In 1 kilograms there are 10,000 decigrams.

1 kilo gram = 10,000 deci grams

So, 0.005 kg will be equal to:

0.005 kg = 0.005\times 10,000 dg = 50 dg

There are 50 decigrams in 0.005 kilo grams.

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Is salt water solution a homogeneous mixture
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yes, it is a homogeneous mixture because the different parts cannot be seen.

Explanation:

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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
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Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
3 years ago
Which of the following BEST describes a process by which metamorphic rock becomes igneous rock?
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Answer:

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Explanation:

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2 years ago
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26.0 g of a liquid that has a density of 1.44 g/mL needs to be measured out in a graduated cylinder. what volume should be used
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As Density = Mass/Volume
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The half life of plutonium-239 (239pu, pu-239) is 24,100 years. How much plutonium will remain after 1000 years if the initial a
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The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g

The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

n=1000/24100=0.0414

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The mass remaining is 2.5 g

  • The half life is the time in which the concentration of a substance decreases to half of the initial value.

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