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3 years ago

Green light has a frequency of 6.01 x 10^14 Hz. What is the wavelength?

Chemistry

2 answers:

Scrat [10]3 years ago

7 0

Answer : The wavelength of green light is $4.99\times 10^{-7}m$

Explanation : Given,

Frequency of green light = $6.01\times 10^{14}Hz=6.01\times 10^{14}s^{-1}$

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of light

$\lambda$ = wavelength of light

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$6.01\times 10^{14}s^{-1}=\frac{3\times 10^8m/s}{\lambda}$

$\lambda=4.99\times 10^{-7}m$

Therefore, the wavelength of green light is $4.99\times 10^{-7}m$

Lady_Fox [76]3 years ago

6 0

Wavelength=speed over frequency.
v/f.
so you need to know the speed of green light to find out wavelength.

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A teapot with a surface area of 785 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic

lina2011 [118]

Answer:

Given info: The surface area of teapot plated with silver is 700 cm2700 cm2, the cell is powered by 12.0-V12.0-V, the resistance of the cell is 1.80 Ω1.80 Ω, thickness of silver layer is 0.133-mm0.133-mm and density of silver is 10.5×103 kg/m310.5×103 kg/m3.

Write the expression for the mass of the silver.

m=ρAdm=ρAd (1)

Here,

ρρ is the density of silver.

AA is the surface area.

dd is the thickness of the silver layer.

Substitute 10.5×103 kg/m310.5×103 kg/m3 for ρρ, 700 cm2700 cm2 for AA and 0.133-mm0.133-mm for dd in equation (1) to find mass of the silver.

m=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 gm=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 g

Thus, the mass of silver is 97.8 g97.8 g.

Write the expression for number of moles of silver.

n=mWan=mWa (2)

Here,

mm is the mass of silver.

WaWa is the atomic weight.

The atomic weight of silver is 107.8 g/mole107.8 g/mole

Substitute 97.8 g97.8 g for mm, and 107.8 g/mole107.8 g/mole for WaWa in equation (2) to find number of moles of silver.

n=97.8 g107.8 g/mole=0.907 moln=97.8 g107.8 g/mole=0.907 mol

Thus, the number of moles of silver is 0.907 mol0.907 mol.

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4 years ago

Identify the gas particle that travels the slowest. ne h2 co n2 o2

Evgen [1.6K]

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4 years ago

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An ideal gas is confined to a cylinder by a piston. The piston is slowly pushed in so that the gas temperature remains at 20 deg

HACTEHA [7]

Answer:

vhgbvbhdf

Explanation:

(a) It is given that the gas is ideal. Formula for change in entropy of the gas according to the first law of thermodynamics is as follows.

$\Delta U = dQ - dW$

For isothermal process, $\Delta U = 0$ at constant temperature.

So, $\Delta U = dQ - dW$

$0 = dQ - dW$

or, dQ = dW = 730 J

Now, according to the second law of thermodynamics the entropy change is as follows.

$\Delta S = \frac{dQ}{dT}$

= $\frac{730 J}{293.15 K}$

= 2.490 J/K

Therefore, the entropy change of the gas is 2.490 J/K.

(b) In the given process, at constant temperature the gas will be compressed slowly because then kinetic energy of the gas molecules will also be constant. The volume decreases so that the movement of molecules increases as a result, entropy of molecules will also increase.

This means that $\Delta S = 2.490 J/K > 0$

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3 years ago

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choli [55]

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3 years ago

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Calculate the standard potential, e∘, for this reaction from its equilibrium constant at 298 k. x(s)+y4+(aq)↽−−⇀x4+(aq)+y(s)k=4.

laila [671]

First, we need to get the number of moles:

from the reaction equation when Y4+ takes 4 electrons and became Y, X loses 4 electrons and became X4+

∴ the number of moles n = 4

we are going to use this formula:

㏑K = n *F *E/RT

when K is the equilibrium constant = 4.98 x 10^-5

and F is Faraday's constant = 96500

and the constant R = 8.314

and T is the temperature in Kelvin = 298 K

and n is number of moles of electrons = 4

so, by substitution:

㏑4.98 x 10^-5 = 4*96500*E / 8.314*298

∴E = -0.064 V

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3 years ago