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3 years ago

Identify the gas particle that travels the slowest. ne h2 co n2 o2

2 answers:

5 0

<span>O2 travels slower than H2, Ne, N2, and CO. This is due to the fact that O2 has a heavier molecular weight than the others. O2 has a weight of 32 grams per mole. N2 and CO are the next highest with 28 grams per mole. Ne is 20 grams per mole, and H2 is 2 grams per mole.</span>

Zanzabum3 years ago

4 0

Answer:

Explanation:

The distribution of the speed of gas particles is represented via a Maxwell-Boltzmann graph which is essentially a plot of the velocity of gas particles vs the fraction of gas particles.

A proper assessment of the velocity can be made by measuring the root mean square velocity of the particles which is given as:

$v_{rms} =\sqrt{\frac{3RT}{M} } ----(1)$

where, R = gas constant = 8.314 J/mol-K

T = temperature of gas in K

M = molecular weight of the gas

Based on equation (1), the velocity of the gas particle is inversely proportional to its molecular weight.

The molecular/atomic weights of the given gases are:

Ne = 20 g/mol

H2 = 2 g/mol

CO = 28 g/mol

N2 = 28 g/mol

O2 = 32 g/mol

Since O2 has the highest molecular weight, it will travel the slowest.

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2 years ago

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2 years ago

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andrew11 [14]

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2 years ago

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve

pochemuha

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.

The balanced neutralization equation is:

NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)

Step 1: Calculate the reacting moles of KHP.

0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.

0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol

Step 2: Determine the reacting moles of NaOH.

The molar ratio of NaOH to KHP is 1:1.

1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH

Step 3: Calculate the molarity of NaOH.

1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.

[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Learn more about titration here: brainly.com/question/4225093

3 0

2 years ago

What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.

insens350 [35]

The mass of a sample of alcohol is found to be = m = 367 g

Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.

Explanation:

The Energy of the sample given is q = 4780

We are required to find the mass of alcohol m = ?

Given that,

The specific heat given is represented by = c = 2.4 J/gC

The temperature given is ΔT = 5.43° C

The mass of sample of alcohol can be found as follows,

The formula is c = $\frac{q}{mt}$

We can drive value of m bu shifting m on the left hand side,

m = $\frac{q}{ct}$

mass of alcohol (m) = $\frac{4780}{(2.4)( 5.43)}$

m = 367 g

Therefore, The mass of the given sample of alcohol is

m = 367g

It requires 4780 J of heat to raise the temperature by 5.43 C in the process which yields a mass of 367 g of alcohol.

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3 years ago