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3 years ago

Identify the gas particle that travels the slowest. ne h2 co n2 o2

2 answers:

5 0

<span>O2 travels slower than H2, Ne, N2, and CO. This is due to the fact that O2 has a heavier molecular weight than the others. O2 has a weight of 32 grams per mole. N2 and CO are the next highest with 28 grams per mole. Ne is 20 grams per mole, and H2 is 2 grams per mole.</span>

Zanzabum3 years ago

4 0

Answer:

Explanation:

The distribution of the speed of gas particles is represented via a Maxwell-Boltzmann graph which is essentially a plot of the velocity of gas particles vs the fraction of gas particles.

A proper assessment of the velocity can be made by measuring the root mean square velocity of the particles which is given as:

$v_{rms} =\sqrt{\frac{3RT}{M} } ----(1)$

where, R = gas constant = 8.314 J/mol-K

T = temperature of gas in K

M = molecular weight of the gas

Based on equation (1), the velocity of the gas particle is inversely proportional to its molecular weight.

The molecular/atomic weights of the given gases are:

Ne = 20 g/mol

H2 = 2 g/mol

CO = 28 g/mol

N2 = 28 g/mol

O2 = 32 g/mol

Since O2 has the highest molecular weight, it will travel the slowest.

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The heat of fusion for water is 80. cal/g. how many calories of heat are released

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800 calories are released

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2 years ago

When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _

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Balancing redox reactions:

Oxygen should be balanced by adding $H_{2}O$ as needed, while hydrogen should be balanced by adding $H^{+}$ .

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding $H_{2}O$ , $H^{+}$ , and $e^{-}$ in that order, each reaction is brought into equilibrium:

By putting the right number of water ( $H_{2}O$ ) molecules on the other side of the equation, the oxygen atoms are brought into balance.
By adding $H^{+}$ ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
Total the fees for each side. Add enough electrons ( $e^{-}$ ) to the more positive side to make them equal. (As a general rule, $e^{-}$ and $H^{+}$ are nearly always on the same side.)
The $e^{-}$ on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
Now that the equation has been verified, it can be balanced.

Learn more about redox reaction here,

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2 years ago

This question is about iron three of the raw material added to a blast furnace used to extract iron from henatite are coke hemat

IrinaVladis [17]

Answer: The fourth material that is added to the blast furnace is HOT AIR which provides OXYGEN for used for combustion of carbon (Coke).

Explanation:

Iron is the second most abundant metal found in the earth's crust after aluminium. It is not found in the free metallic state but are extracted from rocks which are rich in iron that contains other materials. These are known are iron ores and the most common iron ores are haematite ( Fe2O3).

Iron can be extracted from its ore with the used of blast furnace. The materials used for extraction of iron includes:

--> Coke

--> haematite( iron ore)

--> limestone and

--> Hot air.

The iron ore is first roasted in air so that iron(III)oxide is produced. The iron(III)oxide is then mixed with coke and limestone and heated to a very high temperature. Hot air is introduced into it from the bottom of the furnace. The coke is oxidizes the the oxygen in the hot air blast to liberate carbondioxide.

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How many moles are in 71.7 g of pure aluminum?

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Answer:

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