Answer:
Fraction of water that can be vaporized = 0.0961 or 9.61%
<em>Note : The question is incomplete. The complete question is given below:</em>
<em>A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body.</em>
<em>If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what fraction of the water would be vaporized?</em>
Explanation:
Energy released by a serving of Cheeze-Its = 130 kcal
Since 1 kcal = 4.18 kJ, 130 kcal = 130 * 4.18 kJ = 543.4 kJ
Heat of vaporization (evaporating or condensing) Hv, of water = 2260 J/g
From formula, quantity of heat, Q = mass * heat of vaporization
mass of water = 2.5 kg = 2500 g
Q = 2500 g * 2260 J/g
Q = 5650000 J = 5650 kJ
Therefore 2.5 kg of water requires 5650 kJ of heat for complete vaporization
Fraction of water that can be vaporized by 543.4 kJ energy = 543.4/5650
Fraction of water that can be vaporized = 0.0961 or 9.61%
Answer:
2.29 m.
Explanation:
The following data were obtained from the question:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mass of water = 329 g
Molality of KOH = ?
Next, we shall determine the number of mole in 42.3 g of KOH. This can be obtained as follow:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mole of KOH =?
Mole = mass /Molar mass
Mole of KOH = 42.3/56.11
Mole of KOH = 0.754 mole
Next, we shall convert 329 g of water to kilogram (kg). This can be obtained as follow:
1000 g = 1 kg
Therefore,
329 g = 329 g /1000 g × 1 kg
329 g = 0.329 kg
Therefore, 329 g of water is equivalent to 0.329 kg
Finally, we shall determine the molality of the KOH solution ad follow:
Molality is defined as the mole of solute per unit kilogram of solvent (water) i.e
Molality = mole/ mass (kg) of water
Mole of KOH = 0.754 mole.
Mass of water = 0.329 kg.
Molality = mole/ mass (kg) of water
Molality = 0.754/0.329
Molality = 2.29 m
Therefore, the molality of the KOH solution is 2.29 m.
<h3>
Answer:</h3>
1.54 × 10²⁴ atoms He
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 2.56 moles He
[Solve] atoms He
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.54163 × 10²⁴ atoms He ≈ 1.54 × 10²⁴ atoms He
Answer:
According to Mr. Newton, an object will only accelerate if there is “net force” acting upon it. A net force is the sum of all forces acting on an object. A net force is capable of accelerating a mass.
Explanation:
