20= 14+8x help please

A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of

daser333 [38]

Options were missing in the question;

A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of paper do you need to make a cup? Use 3.14 to approximate pi.

24 square inches

31 square inches

47 square inches

52 square inches

Answer:

24 square inches

Step-by-step explanation:

Given:

Diameter = 3 in

So we can say that;

Radius is half of diameter.

radius (r) = $\frac{3}{2}=1.5\ in$

Slant height (l) = 5 in

We need to find how many square inches of paper do you need to make a cup.

Solution:

Now according to question we required to find the amount of paper used to make cup.

Also Water cup is shaped liked cone.

Hence we can say that the base of cone is not covered since it will remain open.

So we will use Lateral surface area of the cone to find the paper requirement.

Now we know that;

Lateral surface area of cone is equal to π times radius times slant height.

framing in equation form we get;

$A_L = \pi rl=3.14\times1.5\times5 = 23.55 in^2 \approx 24\ in^2$

Hence We can say that 24 square inches of paper will be needed to make the cup.

5 0

3 years ago

An arithmetic sequence has this recursive formula:

AnnZ [28]

Answer:

A

Step-by-step explanation:

Sn=a(n-1) d

this formula for Calculating arithmetic sequence

7 0

3 years ago

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What is the length of DE in the right triangle below ?

olganol [36]

B.25
sorry if my writing is not clear

3 0

3 years ago

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For the following system, use the second equation to make a substitution for why in the first equation. Will mark brainlyest!

Alona [7]

Answer:

b

Step-by-step explanation:

get y by itself in the second equation: y= 2x-3

substitute this into the y of the first equation:

2x+2x-3= 5

7 0

3 years ago

How many numbers can you make between 0-99 using exactly four 4s?

MAVERICK [17]

Answer:

Number Four Fours Term Solved By

0 4 - 4 + 4 - 4 johnv

1 (4/4) / (4/4) johnv

2 4/4 + 4/4 pilot

3 (4+4+4) / 4 pilot

4 [ (4/4) ^4 ] * 4 catbells

5 [ 4*4 +4 ] / 4 pilot

6 [ (4+4) /4 ] +4 scruffy

7 4+4 - (4/4) Flora Flatbelly

8 4*4 - 4 - 4 catbells

9 4/4 +4 +4 scruffy

10 4 + √4 + √4 + √4 P Rubie

11 44 / (√4 + √4) christina

12 4 + 4 + √4 + √4 johnv

13 4!/(√4) + 4/4 tackline

14 4+4+4 + √4 D12Bit

15 (44/4)+4 D12Bit

16 4*4*4 / 4 D12Bit

17 4*4 + 4/4 D12Bit

18 4*4 + 4 / √4 D12Bit

19 4! - 4 - 4/4 ?

Solutions to the Second Challenge: 20 to 99

Number Four Fours Term Solved By

20 4 * 4 + √4 + √4

21 4! - 4 + 4/4

22 4! - (4! / 4 - 4)

23 4! - 4^(4-4)

24 4 * ( 4 + 4/√4 )

25 4! + 4^(4-4)

26 4! + (4! / 4 + 4)

27 4! + 4 - 4/4

28 4! + 4 * (4/4)

29 4! + 4 + 4/4

30 (4 + 4/4)! / 4

31 (4! + 4)/4 +4! MicheleR

32 4*4 + 4*4

33 (4 - .4)/.4 + 4! IceMantis

34 4*4 * √4 + √

35 4! + 44/4

36 4*4 * √4 + 4

37 4! + (4! + √4) / √4 christina

38 44 - 4 - √4

[39] 4! + 4! - 4/.4~

40 44 - √4 - √

41 (4*4 + .4) / .4

42 44 - 4/√4

43 44 - 4/4

44 44 + 4 - 4

45 44 + 4/4

46 44 + 4/√4

47 4! + 4! - 4/4

48 44 + √4 + √4

49 4! + 4! + 4/4

50 44 + 4! / 4

51 (4! - 4 + .4) / .4 Mr.B

52 44 + 4 + 4

[53] 44 + 4 / .4~

54 4! + 4! + (4! / 4)

55 [4! - ( 4 / √4 ) ] IceMantis

56 44 + 4! / √4

[57] 4! + 4! + 4/.4~

58 4! + 4! + 4/.4 IceMantis

59 4!/.4 - 4/4 FireMantis

60 44 + 4 * 4

61 4!/.4 + 4/4 FireMantis

62 (4 + 4) ^ √4 - √4

63 (4! + √4) / .4 - √4 FireMantis

64 4 * 4 * √4 * √4

65 (4^4 +4) / 4 Jeremy

66 (4 + 4) ^ [√4] + √4

67 [4! + √4] / .4 + √4 FireMantis

68 (4 + 4) ^ √4 + 4

69 (4!+4-.4)/.4 Partick

70 44 + 4! + √4 FireMantis

71 (4 + 4! + .4) / .4 IceMantis

72 [ (4! / 4) ^ √4 ] * √4

[73] [4! * √4 + √.4~)] / √.4~) capOCC

74 4! + 4! + 4! + √4 FireMantis

75 (4! + √4 + 4) / .4 FireMantis

76 4!*4 - 4! + 4 Jeremy

[77] (4/.4~) ^ √4 - 4 FireMantis

78 √4 / .4~) * [4! + √4] ArBeeJay Ruakura

79 (4/.4~) ^ √4 - √4

80 4! * 4 - 4*4 -

[81] (4/.4~) * (4/.4~) -

82 (4! / .4) + 4! - √4 Partick

[83] (4/.4~) ^ √4 + √4 -

84 4! * 4 - 4! / √4 -

[85] (4/.4~) ^ √4 + 4 -

86 4!*4 - 4/.4 IceMantis

87 4! * 4 - 4/.4~ -

88 4! * 4 - 4 - 4 -

89 4! + [4! + √4]/.4 RyVikOCC

90 4! * 4 - 4! / 4 -

91 4 * 4! - (√4 / .4) IceMantis

92 4! * 4 - √4*4) -

[93] 4 * 4! - [ √4 / √(.4~) ] IceMantis

94 4! * 4 - 4/√4 -

95 4! * 4 - 4/4 -

96 4! * 4 + 4 - 4 -

97 4! * 4 + 4/4 -

98 4! * 4 + 4/√4 -

[99] (4!*√4-4) / .4~ IceMantis

Step-by-step explanation:

7 0

3 years ago

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