3x-12 ≥7x+4
Subtract 3x from both sides
-12 ≥4x+4
Subtract 4 from both sides
-16 ≥4x
Divide each side by 4
-4 ≥x
From point 4, you use a closed circle and the arrow is facing towards 0
Answer:
(x,y) = (8,7)
Step-by-step explanation:
Solve equation [2] for the variable x
[2] x = y + 15
Plug this in for variable x in equation [1]
[1] (y +15) + y = 1
[1] 2y = -14
Solve equation [1] for the variable y
[1] 2y = - 14
[1] y = - 7 By now we know this much :
x = y+15
y = -7
// Use the y value to solve for x
x = (-7)+15 = 8
Solution :
{x,y} = {8,-7}
I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.
.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,
[B]-[C][F]=
[B]-[C][F]=
.
.
.
If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=
Answer:
the answer is <em><u>1</u></em><em><u>1</u></em><em><u>7</u></em><em><u>8</u></em><em><u>8</u></em> :) your welcome
Answer:
OPTION D: NEITHER
Step-by-step explanation:
The given equation is: 7x - 2y = - 5
To find a solution to this, we substitute the options and compare LHS and RHS.
OPTION A: (1, 5)
LHS = 7(1) - 2(5) = 7 - 10 = -3
RHS = - 5
LHS 
RHS.
So, this option is eliminated.
OPTION B: (-1, 1)
LHS = 7(-1) - 2(1) = -7 - 2 = - 9
RHS = - 5
Again, LHS RHS.
So, this Option is eliminated as well.
OPTION C: It says both A and B. Clearly, this is eliminated as well.
Therefore, the answer is: OPTION D: NEITHER.
NOTE: This is a two variable equation. So, we need a minimum of two equations to determine the solution. Since, only one equation is given here, we use the help of options.
