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ira [324]
2 years ago
8

Marcos is flying a kite 35 feet above an oak tree. The angle of elevation to the top of the tree is 16 and the angle of elevatio

n to the kite is 25'. pleaseee

Mathematics
1 answer:
cricket20 [7]2 years ago
3 0

Answer:

195 ft.

Step-by-step explanation:

I don't have an actual explanation because I simply guessed based on the dimensions and what made the most sense and I got it right. If someone has an explanation as to why it is 195 ft please lmk. Other than that, 195 ft is the correct answer.

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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
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Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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