Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
slope = change in y / change is x
slope = rise / run
change in y = -1 (goes down 1)
change is x = 4 (goes right 4)
slope = -1/4
y-intercept, when x = 0
y-intercept = 1 = (0,1)
Toni can carry up to 5 books
1+2+3b=18
combine 1 and 2
3+3b=18
subtract 3 from both sides
3b=15
divide 3 from both sides
b=5
The answer that will not result in a congruent figure is the statement about moving the points so they are 2/3 as far from the y-axis.
If you take the 2 top points on the trapezoid and test this, you will see they will not end up the same distance apart. Currently, they are 3 units apart.
2/3 of 6 = 4 units from the y-axis
2/3 of 3 = 2 units from the y-axis
This new figure would only be 2 units apart on the top.
