Molar mass Na2SO4 = <span>142.04 g/mol
142.04 g -------------- 6.02x10</span>²³ atoms
?? g ------------------ 7.4x10²³ atoms
142.04 x ( 7.4x10²³) / 6.02x10²³
=> 174.60 g
Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as , and in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Answer:
Explanation:
<u>Chemical formulas for every compound:</u>
Potassium vapor =>
Molten soldium chloride =>
Molten Potassium chloride =>
Molten Sodium Metal =>
<u>The reaction will be as follows:</u>
This reaction is usually called displacement reaction in which an element displaces another element of a compund.
Answer:
the water hardness caused by the presence of the dissolved bicarbonate minerals