If iron (Fe) gained a proton it would become cobalt (CO).
12+12+6(1)+16 =46 46*.251 = 11.546 gram
Explanation:
Air has a heat capacity of about 700 Joules per kg per °K and a density of just 1.2 kg/m3, so its initial energy would be 700 x 1 x 1.2 x 293 = 246,120 Joules
Answer:
7.35atm
Explanation:
Data obtained from the question include:
V1 = 28L
T1 = 42°C = 42 + 273 = 315K
P1 =?
V2 = 49L
T2 = 27°C = 27 + 273 = 300K
P2 = 4atm
Using P1V1/T1 = P2V2/T2, the original pressure can be obtained as follows:
P1V1/T1 = P2V2/T2
P1 x 28/315 = 4 x 49/300
Cross multiply to express in linear form
P1 x 28 x 300 = 315 x 4 x 49
Divide both side by 28 x 300
P1 = (315 x 4 x 49) /(28 x 300)
P1 = 7.35atm
Therefore, the original pressure is 7.35atm
