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sertanlavr [38]
3 years ago
14

What happens to the Subatomic particles of an object when it is charged by induction?

Chemistry
1 answer:
irina1246 [14]3 years ago
3 0
The electrons are forced to move away from the induction as a negative charge builds up on one side of the object - it basically repels the force of the charger, leaving protons with an opposite charge on the other side of the object. The object still remains neutral, its protons have just shifted.
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Which of the following in the definition of control?
Advocard [28]
D The Part That Stays The Same
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3 years ago
PI3Cl2 is a nonpolar molecule. Based on this information, determine the I−P−I bond angle, the Cl−P−Cl bond angle, and the I−P−Cl
alexdok [17]

Answer: Yes I-P-Cl = 90

Explanation:

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3 0
3 years ago
A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}

Where,

m_{solute} = Given mass of solute (KOH) = 3.301 g

M_{solute} = Molar mass of solute (KOH) = 56.1 g/mol

W_{solvent} = Mass of solvent = 96.699 g

Putting values in above equation, we get:

\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m

Hence, the molality of potassium hydroxide solution is 0.608 m

4 0
3 years ago
Which of these statements is true about photons?
Yuliya22 [10]

Answer: it’s a I believe

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6 0
2 years ago
What is the volume of an alka seltzer tablet
Delicious77 [7]

Answer:

Explanation:

Alka Seltzer tablet contains 325 mg of aspirin (acetylsalicylic acid), 1000 mg of citric acid, and 1916 mg of sodium bicarbonate. The acids originally contained in a tablet give only 17.4 mmol of H+, which is not enough to neutralize all of the sodium bicar- bonate (22.8 mmol).

3 0
3 years ago
Read 2 more answers
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