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Marizza181 [45]
1 year ago
8

How much would the boiling point of water increase if mol of NaCl added 1 kg of water (Kb= 0.51 degrees Celsius /(mol/kg) for wa

ter i=2 for NaCl
Chemistry
1 answer:
Valentin [98]1 year ago
3 0

The boiling point of water would increase by 1°C if 1 mol of NaCl added 1 kg of water.

<h3>What would be the change in the boiling point of water when NaCl is added to it?</h3>

The addition of solute substances to solvent such as water results in a change in the boiling points and freezing points of the solvents.

The formula to calculate the change in temperature is given below:

ΔT = Kbmi

Where;

m is molality of the solution

Kb and i are constants.

Solving for change in temperature:

m = 1 mol/kg

ΔT = 0.51 * 1 * 2

ΔT = 1°C

The normal boiling point of water is 100°C

The new boiling point of the solution = (100 + 1) = 101 °C

In conclusion, addition of solute to solvent will result in change in the boiling point of the solvent.

Learn more about boiling point at: brainly.com/question/14557986

#SPJ1

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If air is 80 percent nitrogen and 20 percent oxygen by volume what is density
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1 mol of any gas or mix of gases at STP conditions will have a volume of 22.4 L. Since the problem doesn’t said what are the conditions I will asume that are STP condition and the volume of one mole of the mix will have a volume of 22.4 L.

You may know that density is
D=m/v

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The entropy of a sample of CO2 increases as the CO2 changes from
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Read 2 more answers
Arunner sprints 550 feet in 100 seconds. If the runner can hold this pace for an hour
Alex
<h3>Answer:</h3>

Distance traveled is 9.055 km

<h3>Explanation:</h3>

Speed is given by dividing distance by time.

The distance given is 550 ft and the time is 100 seconds.

Therefore; Speed = 550 ft ÷ 100 sec

                              = 5.5 ft/sec

We can calculate the distance the runner covered in one and half hour.

Time = 1.5 hours

But 1 hour = 3600 sec

1.5 hours = (1.5 × 3600)

               = 5400 sec

Distance is given by multiplying speed and time

Thus; Distance = 5.5 ft/sec × 5400 sec

                         = 29700 ft

But; 1 m = 3.28 ft

1000 m = 1 km

Therefore; 29700 ft will be equivalent to

 = 29700 ft/3.28 ft

= 9054.878 M

but 1000 m = 1 km

Thus, distance = 9054.878 ÷ 1000 m

                        = 9.055 km

6 0
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