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Nikolay [14]
3 years ago
5

Solve -vp + 30 < 45 for v..

Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0
<span> -vp + 30 < 45 for v.

</span> -vp  < 15
v > -15/p

hope it helps
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(-6x) / (-2)<br> Simplify.<br><br> 12x<br> 4x<br> 3x<br> 1/12x
ElenaW [278]

\dfrac{-6x}{-2}=\dfrac{-6}{-2}x=3x

8 0
2 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

f(x) = 4x^2 - 3x + 6

6 0
3 years ago
What is the answer for this -12n - (-13n)=
Ksenya-84 [330]

Answer:

n

Step-by-step explanation:

-12n - (-13n) = -12n +13n = 1n

8 0
2 years ago
A television normally sells for $320. This week, it's on sale at 60% of the normal price. What is the sale price?
Evgesh-ka [11]
You would take 320 and multiply it by .60 and you would get 192. So the answer is B) $192.
3 0
3 years ago
Read 2 more answers
Jay estimates that a basketball weights about .5 pounds. Shawna estimates that a basketball weights about.05. Whose estimate is
Natasha_Volkova [10]

Answer:

Jay's estimate is closer to the actual weight of the basketball

Step-by-step explanation:

The standard weight of an NBA basketball is 1.4 pounds.

Judging the accuracy of Jay's and Shawna's answer based on their percentage error when compared with the standard, we have that Jay's answer has a lower error as shown below

Error  = (Standard value - Estimated value)/ Standard Value ×100

Error in Jays answer = \frac{1.4 - 0.5}{1.4} × 100 = 64.28 %

Error in Shawna's answer = \frac{1.4 - 0.05}{1.4} × 100 = 96.42%

From this, It is obvious that Jay's answer has a lower percentage error when compared to the actual value.

8 0
3 years ago
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