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3 years ago

Solve -vp + 30 < 45 for v..

Mathematics

1 answer:

julia-pushkina [17]3 years ago

8 0

-vp + 30 < 45 for v.

 -vp < 15
v > -15/p

hope it helps

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F(x) =-6-3x/2. g(x)=2x+4

Advocard [28]

Answer:

correct

Step-by-step explanation:

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3 years ago

Write this equation in Standard Form. Y=2/3x+1

Svet_ta [14]

Write everything on one side
2/3x-y+1=0
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2x-3y+3=0
I hope this is what you're looking for

6 0

3 years ago

.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and

Leni [432]

Answer:

a) Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

b) $t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean for the amount spent each shopper

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

5 0

4 years ago

The following equation is being multiplied by the LCD. Complete the multiplication to eliminate the denominators

frosja888 [35]

Answer:

$(x+2)(x-2) -1(3x)=(x-3)(x-2)$

Step-by-step explanation:

x+2/3x - 1/x-2 = x-3/3x

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LCD is (3x)(x-2). so we multiply the whole equation by LCD

$(3x)(x-2)(\frac{x+2}{3x}-\frac{1}{x-2}=\frac{x-3}{3x})$

We multiply each term by LCD

$(3x)(x-2)(\frac{x+2}{3x})-(3x)(x-2)(\frac{1}{x-2})=(3x)(x-2)(\frac{x-3}{3x})$

$(x+2)(x-2) -1(3x)=(x-3)(x-2)$

4 0

3 years ago

Read 2 more answers

A two-person relay race consists of eight times around a football field. Juan runs four and one-sixth times and Antonio runs thr

Serga [27]

Answer:

Step-by-step explanation:

To convert mixed number as improper fractions, use this rule:

$A\frac{B}C}=\frac{(A*C)+B}{C}$

For Juan: ( $4\frac{1}{6}$ )

$4\frac{1}{6}=\frac{(4*6)+1}{6}=\frac{25}{6}$

For Antonio: ( $3\frac{2}{3}$ )

$3\frac{2}{3}=\frac{(3*3)+2}{3}=\frac{11}{3}$

Answer choice A is correct.

5 0

4 years ago