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2 years ago

Solve -vp + 30 < 45 for v..

Mathematics

1 answer:

julia-pushkina [17]2 years ago

8 0

<span> -vp + 30 < 45 for v.

</span> -vp < 15
v > -15/p

hope it helps

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Choose exactly two answers that are correct.

Lera25 [3.4K]

A and D are both correct answers

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2 years ago

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jessie worked four more hours than Ben. They worked a total of 25 hours. How many hours did each boy workz?

Mandarinka [93]

Answer:

jessie: 14.5

ben: 10.5

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3 years ago

NEED ANSWER ASAP

kkurt [141]

Answer:

$f(2) = 81$

$g(2) = 83$

Science class had a higher average

Step-by-step explanation:

Given

$f(x) = 0.5x + 80$

g(x) table

Solving (a): f(2)

We have:

$f(x) = 0.5x + 80$

So:

$f(2) = 0.5*2 + 80$

$f(2) = 1 + 80$

$f(2) = 81$

Solving (b): g(2)

From the given table.

$g(2) = 83$

Solving (c): f(4) or g(4); which is greater

$f(x) = 0.5x + 80$

So:

$f(4) = 0.5*4+80$

$f(4) = 2+80$

$f(4) = 82$

For g(4): Notice that in the table of g(x); g(x) increases by 2 when x increases by 1

This means that:

$g(x) = g(x-1)+2$

$g(4) = g(4-1)+2:$

$g(4) = g(3)+2$

$g(4) = 85+2$

$g(4) = 87$

<em>Hence, g(4) i.e. Science class is greater</em>

6 0

2 years ago

What are the like terms in the expression?

Anarel [89]

Since none of the terms have the same variables the like terms would be (A) because they are both constants

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2 years ago

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What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

sveta [45]

Answer: A B

Group 1 0.25 0.75

Group 2 0.44 0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

$15+45=60$

Relative frequency of people of A in Group 1 is given by

$\frac{15}{60}=0.25$

Relative frequency of people of B in Group 1 is given by

$\frac{45}{60}=0.75$

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

$20+25=45$

Relative frequency of people of A in Group 2 is given by

$\frac{20}{45}=0.44$

Relative frequency of people of B in Group 2 is given by

$\frac{25}{45}=0.56$

Hence, A B

Group 1 0.25 0.75

Group 2 0.44 0.56

6 0

2 years ago