Using V²=u² +2gH
let's assume the ball falls from rest, then it's initial velocity = 0ms-¹ (U=0)
then from the above info V= 35ms-¹
g= 10ms-² (value of acceleration due to gravity to the nearest tens)
so input your values above into the given formula to find height
35² = 0² +2×10×H
1225 = 20H
H = 1225÷20 = 61.25m
<span>There is an low cost and quickest alternative available for adaptive optics. Name of this technique is wavefront coding. The numerical analysis pretends to show the robustness of the technique under changes in pupil diameter and wavefront shape including intersubject and intrasubject variability, using always the same restoration filter or image decoder .Using this technique it is possible to obtain high resolution images under different ocular aberrations and pupil diameters with the same decoder, opening the possibility of real time high resolution images.</span>
Answer:
why?
Explanation:
Do you need any help on anything else?
1. Protons and Neutrons
2.Inside nucleus
3. Covalent and chemical bonds?
I’m not sure about 3 but other 2 are right lol
Answer:
The responses to this question can be defined as follows:
Explanation:
During energy exchange E=hv, electrodes spring through one orbit to another
Please find the image file in the attachment.
Its absorption layer comprises 0.3 eV, 0.5 eV., 0.8 eV, 2.0 eV, 2.5 eV again, as light passes via material at low temperature those lines absorbed in the strata called absorption stratum.
