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3 years ago

Find the area please and will make brainliest

Mathematics

1 answer:

puteri [66]3 years ago

4 0

To find the area of the trapezoid, we only need the quantities a1 (long base), a2(short base) and h(height).

Area=(1/2)(a1+a2)*h
=(1/2)(9.9+4.7)(5.6)
=40.88 mm ²

Not sure what's expected to give for "type". Perhaps trapezoid or trapezium.

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A radio station had 141 tickets to a concert. They gave away 2 times as many tickets to listeners as to employees. How many tick

erica [24]

Answer:

Option C: 47 tickets

Step-by-step explanation:

Given that:

Tickets given to employees = 1 part

Tickets given to listeners = 2 parts

This means 141 tickets are totally divided into 3 parts so:

1 part = 141/3

1 part = 47

So now,

Tickets given to employees = 1 part = 47 tickets

Tickets given to listeners = 2 parts = 47 *2 tickets = 94 tickets

I hope it will help you!

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=3%5En%5E%2B%5E1%2B9%2F3%5En%5E-%5E1%2B1" id="TexFormula1" title="3^n^+^1+9/3^n^-^1+1" alt="3^n

abruzzese [7]

Answer:

Hello,

Step-by-step explanation:

$\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\$

4 0

2 years ago

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$

5 0

3 years ago

I’m offering 29 points!!!!!!!! AQRS = ATUV Name the angle or side that corresponds to the given part for the question.

ipn [44]

A, C and D because the angles are named in order. Q=T R=U and so on

8 0

3 years ago

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

ExtremeBDS [4]

Answer:

800 kph
600 kph

Step-by-step explanation:

Equation

Let s represent the speed of the faster plane. Then its travel time is ...

time = distance/speed = 3600/s

travel time for the slower plane is ...

time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

3600/(s -200) -3600/s = 1.5

Solution

Multiplying by (2/3)s(s -200), we get ...

2400(s) -2400(s -200) = s(s -200)

s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

(s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

Conclusion

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

Check

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0

2 years ago