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olganol [36]
3 years ago
5

Plz help will mark BRAINLIEST algebra 2

Mathematics
1 answer:
arsen [322]3 years ago
4 0
You have to ask yourself the meaning of h(0)
That means that GS Hopper is at this starting position
h(0) = -0^2 + 4/3 * 0 + 1/4
GS is 1/4 of a unit above the ground. So you need to find out how to solve h(t) so that the value of h(t) = 0 There is a difference between h(t) = 0 and t = 0.

-t^2 + 4/3 t  + 1/4 = 0 I'd multiply through be 12. It might be easier to do.
-12 t^2 + 16t + 3 = 0 Remember all terms have to be multiplied by 12.
I know this seems laborious, but you should divide through by - 1
12t^1 - 16t - 3 = 0. That way you don't have to explain what to do with the minus 1. Negatives can be a real pain.

It does factor. 
(2x - 3)(6x + 1) = 0 This is just a guess that was lucky. You have to try combinations to get it right. Luckily 3 has only 1 and 3 as factors.
2x - 3 = 0
2x = 3
x = 3/2
x = 1.5 This answer means that 1.5 s starts his jump, he's on the ground.

the other root is meaningless. You can't have minus time in these questions.
Answer t = 1.5 s <<<< answer

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The figure is made up of 2 hemispheres and a cylinder.
TiliK225 [7]

the answer is 126p^3

6 0
3 years ago
What is the Mean Absolute Deviation or MAD for each city?
ira [324]

Answer:

A: ⅚

B: ⅚

Step-by-step explanation:

City A: 4, 3.5, 5, 5.5, 4, 2

Mean: sum/n

= 24/6 = 4

|x - mean|: 0, 0.5, 1, 1.5, 0 , 2

MAD = sum|x - mean|/n

5/6 = 0.833

City B: 5, 6, 3.5, 5.5, 4, 6

Mean: 30/6 = 5

|x - mean|: 0, 1, 1.5, 0.5, 1, 1

MAD = sum|x - mean|/n

5/6 = 0.833

3 0
3 years ago
Help!! What is the point in the feasible region maximizes the objection function?
svlad2 [7]

First, find the vertices of the shaded region. You can do this my graphing or by solving a system of equations for each pair of functions. <em>I am going to find them by graphing.</em>

x ≥ 0 and y ≥ 0 place the shaded region in the first quadrant with a vertex at (0, 0)

now graph y ≤ 3.  a vertex is at (0, 3)

now graph y < -2x + 5. a vertex is at (1, 3). the other vertex is the x-intercept (when y = 0).

                  0 = -2x + 5

                  -5 = -2x

                   \frac{5}{2} = x     So, the vertex is  (\frac{5}{2} , 0)

Next, input the coordinates of the vertices into the objective function.

C = -6x + 5y

(0, 0): C = -6(0) + 5(0)

             =    0    +   0

             =          0

(0, 3): C = -6(0) + 5(3)

             =    0    +   15

             =          15

(1, 3): C = -6(1) + 5(3)

             =  -6  +  15

             =       9

(\frac{5}{2} , 0): C = -6(\frac{5}{2}[/tex]) + 5(2)

             =  -15  +  10

             =       -5

The maximum is C = 15 which occurs at vertex (0, 3)

Answer: A


                 


6 0
3 years ago
Shane biked 1 mile less than three times the number of miles lissette biked. Shane biked a total of 7 miles. Write an equation t
ladessa [460]

Answer:

7x3=21-1=20

Step-by-step explanation:

The answer is 7x3=21-1=20

3 0
3 years ago
I'm I doing it right can some 1 explain please
Oliga [24]
To find area (of squares and rectangles), you multiply the sides together. 1.5 (or one and a half; can't make mixed fractions well) times 1.5 doesn't make 1.5. In reality, it makes 2.25. Perimeter doesn't have much to do with area.
6 0
3 years ago
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