A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)
We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday
A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.
The confidence interval of proportions is given by:
π ± z √(π (1-π) /n)
π is the sample proportion.
z is the critical value.
n is the sample size.
For 99% confidence interval the value of z is 2.58
π = 321/650
The confidence interval is given by
=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)
= (0.493846 ± 0.050594)
=(0.4434 , 0.5443)
=(44.34 % , 54.43 %)
Hence a 99% confidence interval for the population mean of high school students that take the bus to school every day is ci=(44.34%, 54.43%)
<u>Learn more about confidence interval:</u>
brainly.com/question/28052710
# SPJ4
12, because 150/25=6x2 is 12
Perimeter 430
Length 172
172 next
430 last(after the =)
Answer:
$7,367.43
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>
![12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)](https://tex.z-dn.net/?f=12cos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%2B10%3D16%5C%5C%5C%5C%5C%5C12cos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%3D6%5C%5C%5C%5C%5C%5Ccos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5C%5Ccos%5E%7B-1%7D%5Cbigg%5Bcos%5Cbigg%28%5Cdfrac%7B2%5Cpi%7D%7B5%7Dx%5Cbigg%29%5Cbigg%5D%3Dcos%5E%7B-1%7D%5Cbigg%28%5Cdfrac%7B1%7D%7B2%7D%5Cbigg%29)
