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DedPeter [7]
3 years ago
5

Compare Boyle's law, Charles's law, and Avogadro's law. a. What remains constant in each law? b. What are the variables in each

law? c. What do the graphs for these laws look like? d. Write each law with V isolated. Using these equations and the graphs from part c, which law(s) show a directly proportional relationship? How can you tell?

Chemistry
1 answer:
zavuch27 [327]3 years ago
8 0

Answer:

a)

In Boyle's Law, the variable that remains constant is the absolute temperature of the gas.

In Charle's Law, the variable that remains constant is the pressure of the gas.

In Avogadro's Law, the variables that remain constant are pressure and temperature of the gas.

b)

In Boyle's Law, the variables involved are pressure and volume: the law states that for a fixed mass of ideal gas at constant temperature, the pressure of the gas is inversely proportional to the volume:

p\propto \frac{1}{V}

where p is the pressure of the gas and V the volume.

In Charle's Law, the variables involved are volume and temperature: the law states that for a  fixed mass of ideal gas at constant pressure, the volume of the gas is directly proportional to the temperature:

V\propto T

where V is the volume of the gas and T the temperature.

In Avogadro's Law, the variables involved are the volume and the number of moles: the law states that for an ideal gas kept at constant pressure and temperature, the volume of the gas is directly proportional to the number of moles:

V\propto n

Where V is the volume of the gas and n the number of moles.

c)

See the graphs of the three Laws in attachment:

- First graph: Boyle's Law, which shows that the pressure of the gas is inversely proportional to the volume

- Second Graph: Charle's Law, which shows that the volume of the gas is directly proportional to the absolute temperature

- Third graph: Avogadro's Law, which shows that the volume of the gas is directly proportional to the number of moles of the gas

d)

Here we want to re-write the three laws by making V the subject.

For Boyle's law, we get:

V\propto \frac{1}{p}

For Charle's Law, we get:

V\propto T

For Avogadro's Law, we get:

V\propto n

Therefore, we see that the two laws that show a direct proportionality are Charle's Law and Avogadro's Law, while Boyle's Law shows an inverse proportionality between the two variables.

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Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

5 0
3 years ago
1. Is this equation balanced? Explain your answer. Na + Cl2 → NaCl ?
Delvig [45]

It is not balanced since there are 2 Cl molecules on the left side, and only 1 on the right side. In order to balance this, you would need to make sure there are the same amount of all the molecules on both sides...

4Na + 2Cl2 = 4NaCl


Hope this helps :)

3 0
2 years ago
In one mole of carbon there are grams of carbon​
fenix001 [56]

Answer: True

Explanation: 1 mole is proportional to the atomic mass of the respective atom (this case carbon) in grams. 12.011

moles = grams

1 mole of carbon = 12.011

i hope you understand bruh

4 0
2 years ago
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What is the kinetic energy of a mole of Ar atoms moving with a speed of 650m/s
Vlad [161]

<em>Molar mass of Argon, Ar = 39.95 g Mass of 1 atom, m = 39.95 / (6.023 * 10^23) = 6.64 * 10^(-23) g =6.64 * 10^(-26) Kg Now, Kinetic Energy, KE = (1/2) * m * v^2 where velocity,v = 650 m/s Mass of 1 atom, m = 6.64 *...</em>

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3 0
3 years ago
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How many grams of NH3 will be produced from a reaction between H2 and NO if the partial pressures of H2 and NO were 536 torr and
Arturiano [62]

Answer:

There will be produced 5.398 grams of NH3

Explanation:

Step 1: Data given

Partial pressure H2 = 536 torr

Partial pressure of NO = 602 torr

Temperature = 150.0°C

Volume = 25.0 L

Reaction yield = 93.5 %

Step 2: The balanced equation

3H2 + 2NO → 2NH3 + O2

Step 3: Calculate moles of H2

p*V = n*R*T

⇒ with p = the pressure of H2 = 536 torr = 536/760 = 0.70526 atm

⇒ with V = the volume = 25.0 L

⇒ with n = the number of moles of H2 = TO BE DETERMINED

⇒ with R= the gas constant = 0.08206 L*atm/mol*K

⇒ with T =the temperature = 150.0 °C = 423 K

n= (0.70526*25.0)/(0.082061$423)

n = 0.508 moles H2

Step 4: Calculate moles NO

p*V = n*R*T

⇒ with p = the pressure of NO = 602 torr = 602/760 = 0.792165 atm

⇒ with V = the volume = 25.0 L

⇒ with n = the number of moles of NO = TO BE DETERMINED

⇒ with R= the gas constant = 0.08206 L*atm/mol*K

⇒ with T =the temperature = 150.0 °C = 423 K

n= (0.792165*25.0)/(0.08206*423)

n = 0.571 moles NO

Step 5: Calculate the limiting reactant

For 3 moles of H2 we need 2 moles of NO to produce 2 moles of NH3 and 1 mole of O2

H2 is the limiting reactant. It will be completely consumed (0.508 moles).

NO is in excess.

Step 6: Calculate moles NH3

For 3 moles of H2 we need 2 moles of NO to produce 2 moles of NH3

For 0.508 moles H2 we'll have 0.339 moles NH3 (This is when the reaction yield is 100%)

For reaction yield of 93.5 % the number of moles = 0.935 * 0.339 = 0.316965 moles NH3

Step 7: Calculate mass of NH3

Mass NH3 = moles NH3 * Molar mass NH3

Mass NH3 = 0.316965 moles NH3 * 17.03  5.398 grams

There will be produced 5.398 grams of NH3

5 0
2 years ago
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