The new volume of the gas is calculated using the Boyles law formula
that is P1V1=P2V2
P1=80 kpa
V1= 500 L
P2=400Kpa
V2=?
by making V2 the subject of the formula V2 =P1V1/P2
=(500 L x80 KPa)/400 KPa = 100 L is the new volume of the gas
Just took the test and it was 32grams. On my test it was Block B: 32 Grams
If theres an all of the above option then I'll pick that if not then, ships
Given:
Moles of H2 = 0.300
Moles of I2 = 0.400
Moles of HI = 0.200
Keq = 870
To determine:
Amounts of the mixture at equilibrium
Explanation:
H2(g) + I2(g) ↔ 2HI(g)
Initial 0.3 0.4 0.2
Change -x -x +2x
Eq (0.3-x) (0.4-x) (0.2+2x)
Keq = [HI]²/[H2][I2]
870 = (0.2+2x)²/(0.3-x)(0.4-x)
x = 0.29 moles
Amounts at equilibrium:
[HI] = 0.2 + 2(0.29) = 0.78 moles
[H2] = 0.3-0.29 = 0.01 moles
[I2] = 0.4-0.29 = 0.11 moles