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JulijaS [17]
3 years ago
14

How many moles of gas are present in 1.13 L of gas at 2.09 atm and 291 K?

Chemistry
1 answer:
raketka [301]3 years ago
3 0
<h2><u>Answer:</u></h2>

n = 0.0989 moles

<h2><u>Explanation:</u></h2>

n = PV / RT

P = 2.09atm

V = 1.13L

R = 0.08206

T = 291K

Plug the numbers in the equation.

n = (2.09atm)(1.13L) / (0.08206)(291K)

n = 0.0989 moles

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A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 93.0 mL
shutvik [7]

Answer:

Mass of solid = 189.141 gram

Explanation:

Given:

Total volume = 93 ml

Mass of liquid = 33.7 gram

Density of liquid = 0.865 g/ml

Density of solid = 3.50 g/ml

Find:

Mass of solid = ?

Computation:

Volume of liquid = Mass of liquid / Density of liquid

Volume of liquid = 33.7 / 0.865

Volume of liquid = 38.9595 ml

Volume of solid = Total volume - Volume of liquid

Volume of solid = 93 - 38.9595

Volume of solid = 54.0405 ml

Mass of solid = Volume of solid × Density of solid

Mass of solid = 54.0405 ml × 3.50 g/ml

Mass of solid = 189.141 gram

7 0
3 years ago
How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?​
AURORKA [14]

Answer:

0.02 mol.

Explanation:

8 0
2 years ago
How many grams of solute are dissolved in 125.0 mL of 5.00 M NaCl (MM = 58.45)?
Nookie1986 [14]

Answer: 36.53g

Explanation:

First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl

Molarity = 5M

MM of NaCl = 58.45

Molarity = Mass conc (g/L) / MM

Mass conc. (g/L) of NaCl = Molarity x MM

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Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)

From the calculations above,

292.25g of NaCl dissolved in 1L

Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e

Xg of NaCl = 292.25 x 0.125 = 36.53g.

Therefore 36.53g of NaCl will dissolve in 125mL of the solution

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6 0
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What evidence did wegener use to create his theory of continental drift?
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