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JulijaS [17]
4 years ago
14

How many moles of gas are present in 1.13 L of gas at 2.09 atm and 291 K?

Chemistry
1 answer:
raketka [301]4 years ago
3 0
<h2><u>Answer:</u></h2>

n = 0.0989 moles

<h2><u>Explanation:</u></h2>

n = PV / RT

P = 2.09atm

V = 1.13L

R = 0.08206

T = 291K

Plug the numbers in the equation.

n = (2.09atm)(1.13L) / (0.08206)(291K)

n = 0.0989 moles

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4 0
4 years ago
Calculate the final molarity of HCl the resulting solution when 5.56 mL of 4.108 M HCl is added to 4.44 mL of water.
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We'll begin by listing what was given from the question. This is shown below:

Initial volume (V₁) = 5.56 mL

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Final volume (V₂) = 5.56 + 4.44 = 10 mL

<h3>Final Molarity (M₂) =? </h3>

The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

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Learn more: brainly.com/question/6103588

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