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Sonbull [250]
3 years ago
9

Im bored someone add my discord and talk to me --> bestface#3185 <--

Chemistry
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

Please don't ask questions like this. People are asking questions that might depend their grade for the year. Please go to another site to say this.

Explanation:

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Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

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Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

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[S] = 1.5 g/L

Enantiomeric excess = \frac {Excess}{Total\ Concentration}\times 100 = \frac {11.5-1.5}{11.5+1.5}\times 100 = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = \frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100

Optical rotation of pure enantiomer = −127 °

76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100

<u>Specific rotation of mixture = - 97.6923 °</u>

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