Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 
point slope form
y-y1 = m(x-x1)
y-9 = 2(x-1)
change to slope intercept form
y-9 = 2(x-1)
distribute
y-9 = 2x-2
add 9 to each side
y = 2x-2+9
y = 2x+7
Answer:
4
Step-by-step explanation:
Well,
First solve the square root which is 7
Funny enough, this makes 7 * 7 = 49
So the answer is 49!
Hope I helped!