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4 years ago

Jessica and Raphael are saving money for concert tickets. Jessica has $20 and saves 10 per week.

1 answer:

8 0

They have the same amount on week 5 ($70)
The Answer would be: $70
((Got this correct on my quiz, If you need it explained, It is below))
The easiest way to do this is to not pay attention to the y=x equation, because the solution is already in the information, this may confuse you and youre wasting time to solve it. Jess has $20 BEFORE saving and gets $10 WEEKLY, Raph has $40 BEFORE saving and gets $6 WEEKLY. In the chart/information, add the amount it takes to get Jess up to $40 then add $10 for every week on going until both their balances are equal. They match on the 5th week with $70 // If the information is different substitute the names/numbers/etc. Hope this helped you and anyone else looking for the answer!

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Yo can someone help me out

amid [387]

Answer:

x = 21

Step-by-step explanation:

corresponding sides in similar polygons are proportional:

set a proportion: BC/FK = CA/KJ => 18/6 = x/7 => x = 18 × 7 ÷ 6 = 21

8 0

3 years ago

Read 2 more answers

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

$k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8$

we get

$k+1=-8\quad$

$k=-9$

$k+1=8\quad$

$k=7$

so,

$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

5 0

3 years ago

The population of a city in 2005 was 18,000. By 2010, the city’s population had grown to 45,000. Economists have determined that

SpyIntel [72]

Exponential model is y=Ae^(kt)
Assume initial start is 2005, time = 0, so y = 18000e^(kt)
45000 = 18000*e^(k5)
solve for k, approx 0.1832
y = 18000*e^(1.832) = 112,435, approximately

6 0

3 years ago

Which statement is true about the graphs of the two lines y = –6 and x =1/6 ?

sweet-ann [11.9K]

These lines are perpendicular because y = -6 is a horizontal line with a slope of 0 and x = 6 is a vertical line with an undefined slope

6 0

3 years ago

Read 2 more answers

Proportional or non proportional?

Ludmilka [50]

Answer:

proportional

Step-by-step explanation:

all are multiplied by 3

7 0

3 years ago