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liubo4ka [24]
3 years ago
15

I drive from Town a to my home and then to town b. The journey time is 50 minutes. What is my average speed ​

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

4 miles per minute

Step-by-step explanation:

Please kindly see the attached file for explanation

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Find the mean, median, mode, and range of the data set.
kompoz [17]

Answer:

mean 11.14

Median 10

mode 10.

Explanation

Mean is sum of data divide by number of data.

Mode is the most appearing number.

3 0
3 years ago
Find m∠PQR. A. 81 B. 90 C. 77 D. 72
AnnZ [28]
<h3>Answer: D. 72</h3>

Work Shown:

Angle PQR = (far arc - near arc)/2

Angle PQR = ( (major arc PR) - (minor arc PR) )/2

Angle PQR = ( (2x+252) - (2x+108) )/2

Angle PQR = 144/2

Angle PQR = 72

Notice how we didn't need to find the value of x at all.

5 0
3 years ago
There are 7052 boys and adults at carnival.
Basile [38]

Answer:

There are 6,296 children at the carnival

Step-by-step explanation:

The number of each group of people can be expressed as;

Number of boys (b)+number of adults (a)=7,052

b+a=7,052....equation 1

Number of girls (g)=Number of adults (a)-756

g=a-756....equation 2

But Number of girls (g)=number of boys (b)

Replacing the value of b in equation 1 with that of g in equation 2;

(a-756)+a=7,052

a+a=7,052+756

2 a=7,808

a=7,808/2

a=3,904

Replace the value of a in equation 2 with 3,904

g=3,904-756

g=3,148

But since g=b

g=b=3,148

b=3,148

Total number of children=Total number of boys (b)+total number of girls (g)

Total number of children=b+g

where;

b=3,148

g=3,148

replacing;

Total number of children=(3,148+3,148)=6,296

There are 6,296 children at the carnival

6 0
3 years ago
Store A advertises a sale for 3 loaves of bread for $5.94. Explain how to use an equivalent rate to find the unit price of the b
rewona [7]
5.94/3= 1.98

Each loaf of bread cost $1.98.

Hope this helps!
6 0
3 years ago
Read 2 more answers
Which of the following relations is a function?
vfiekz [6]
The answer is b. I hope this helps.
3 0
3 years ago
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