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2 years ago

I drive from Town a to my home and then to town b. The journey time is 50 minutes. What is my average speed

Mathematics

1 answer:

Aloiza [94]2 years ago

8 0

Answer:

4 miles per minute

Step-by-step explanation:

Please kindly see the attached file for explanation

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Write 308 as a product of its prime factor

AfilCa [17]

Answer:

Solution: Since, the prime factors of 308 are 2, 7, 11. Therefore, the product of prime factors = 2 × 7 × 11 = 154.

Step-by-step explanation:

3 0

2 years ago

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Which expressions are equivalent to -2(5x-1)+7(5x-1)-3(-5x+1)

blondinia [14]

Answer:

x=1/5

Step-by-step explanation:

To solve this question we will have to open the bracket first

So let's go back to the given question

-2(5x-1)+7(5x-1)-3(-5x+1)

We can actually equate the equation to zero

Let's solve

-10x+2+35x-7+15x-3=0

Let's collect like terms

-10x+35x+15x=-2+7+3

40x=8

Let's make x the subject of formula by dividing both sides by 40

x=1/5

So the final answer is 1/5

8 0

2 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

What is the difference (2 x - 3) - (x - 1)?<br> x minus 4<br> x minus 2<br> x + 2<br> x + 4

kupik [55]

Answer:

x - 2

Step-by-step explanation:

2x - x = x

-3 - -1 = -2

5 0

2 years ago

Read 2 more answers

Explain how you could estimate 16% of $118.56 to check if your answer is reasonable.

denis23 [38]

You could multiply 118.56 by .16 which is 19 dollars rounded and subtract 19 from 117.56 to get your answer

6 0

3 years ago

I drive from Town a to my home and then to town b. The journey time is 50 minutes. What is my average speed ​

I drive from Town a to my home and then to town b. The journey time is 50 minutes. What is my average speed