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Katarina [22]
3 years ago
5

PLEASE HELP WITH MATH..... Three randomly selected households are surveyed. The numbers of people in the households are 1, 4 and

10. Assume that the samples of size n=2 are randomly selected with replacement from the population of 1, 4 and 10. Listed below are the nine different samples: 1,1 1,4 1,10 4,1 4,4 4,10 10,1 10,4 10,10 Find the variance of each of the nine samples: (find s^2 and probability) s^ 2 is 4.5, 0, or 1 ? Whats the probability? s^2 is 9, 4.5, 2.3 ? Whats the probability? s^2 is 18, 72, or 9? Whats the probability? s^2 is 20.3, 81 or 40.5? Whats the probability?
Mathematics
1 answer:
dem82 [27]3 years ago
7 0
<span>We have the following cases to consider (1,1), (1,4), (1,10) ,(4,4) (4,10), (10,10). Well we know three of our samples will have a variance of 0. The variance for the case when we have 1 and 4 is 4.5; likewise, the variance for when we have 10 and 4 is 18 and the variance for when we have 1 and 10 is 40.5. The possible variances are 0, 4.5, 18, and 40.5. The probability of having a variance of 0 is 3/9. For a variance of 4.5 its 2/9, for 18 its 2/9 and lastly, for a variance of 40.5 its 2/9. As you can see, 3/9 + 2/9 + 2/9 + 2/9 = 1.</span>
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Korolek [52]

Given:

Time has a total of $28 after spending half of his weekly earnings on a video game and earning $10 additional dollars for mowing the lawn.

To find:

Weekly earnings at his part time job.

Solution:

Let x be the weekly earning.

He spend half of his weekly earning, i.e., \dfrac{x}{2}

He earns $10 additional dollars for mowing the lawn.

According to the question,

\dfrac{x}{2}+10=28

\dfrac{x}{2}=28-10

\dfrac{x}{2}=18

Multiply both sides by 2.

x=36

Therefore, his weekly earnings is $36.

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Alternatively, you can use substitution to solve for your answer.

Step-by-step explanation:

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Step-by-step explanation:

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Suppose an investment account is opened with an initial deposit of $11,000 earning 7.2% interest. Round all answers to the neare
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8 0
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In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the
ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

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Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

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And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0
3 years ago
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