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Karolina [17]
3 years ago
9

Put the following steps of specimen preparation and staining in order: I. Application of staining dyes II. Heat fixation III. Sm

ear preparation A. II, III, I B. III, II, I C. I, III, II D. III, I, II
Chemistry
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

Explanation:

II

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The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its el
Nataly [62]

The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C            83.87       12                     \frac{83.87}{12} = 6.98                   \frac{6.98}{0.25} = 3

H            11.99         1                       \frac{11.99}{1} = 11.09                  \frac{11.09}{0.25} = 4

O            4.14          16                      \frac{4.14}{16} = 0.25                    \frac{0.25}{0.25} = 1

Thus the empirical formula is C₃H₄O₁.

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = \frac{\text{Molecular weight}}{\text{Empirical formula weight}}

  = \frac{386.64}{56}

  = 7

Molecular formula = Empirical formula × n

                               = 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

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