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Llana [10]
3 years ago
10

What are the three different types of selective breeding

Chemistry
1 answer:
balandron [24]3 years ago
3 0

first of all there is only two types of selective breeding and they are hybridization and inbreeding.

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PLEASE HELP
LenaWriter [7]

Hello!


I don't know a lot of this but after doing just a bit of research I think the answer is either A. or C. but I think it is A.


Hope it helps?

5 0
3 years ago
Determine if the following statements are true or false. True Standard reduction potential is an intensive property True Reducti
tensa zangetsu [6.8K]

Answer:

Standard reduction potential is an intensive property---- True

Reduction takes place at the anode ----- False

The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false

The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell  ------  True

Explanation:

An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.

In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).

4 0
3 years ago
How do atoms explain the pattern that the mass of the products always equals the mass of the reaction?
galina1969 [7]
The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. ... Because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products.
7 0
3 years ago
One photon of a certain type of light has an energy of 7.32x10^-19 J. a.) What is the frequency of this type of light? b.) What
iren [92.7K]

Answer:

f = 1.1041 × 10¹⁵ s⁻¹

λ = 2.72  × 10⁻⁷ m

Explanation:

Given data:

Energy of photon = 7.32 × 10⁻¹⁹ J

Wavelength = ?

Frequency = ?

Solution:

Formula

E = h. f

h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s

Now we will put the values in equation

f = E/h

Kg.m²/s² = j

f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s

f = 1.1041 × 10¹⁵ s⁻¹

Wavelength of photon.

E = h.c /λ

λ =  h. c / E

λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²

λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m

λ = 2.72  × 10⁻⁷ m

7 0
3 years ago
To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mL sample of
nalin [4]

Answer:

Calculated density = 0.8555g/ mL

Probable identity = Toulene

Explanation:

First off, the substance choices are;

isopropyl alcohol (density 0. 785 g/ mL)

toluene ( density 0.866g/ mL)

So upon calculation, if the density of the liquid substance is equal to either of the substances in the choice, it is that substance.

The relationship between density, mass and volume is given as;

Density = Mass / Volume

Mass = 38.5g

Volume = 45ml

Density = 38.5 / 45 = 0.8555g/ mL

Calculated density = 0.8555g/ mL

Among both substances, it is closest to  toluene ( density 0.866g/ mL).

Probable identity = Toulene

8 0
3 years ago
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