<h3>
Answer:</h3>
CdS
<h3>
Explanation:</h3>
<u>We are given;</u>
- % of cadmium is 78%
- % of sulfur is 22.0%
We are required to determine the empirical formula of cadmium sulfide
<h3>Step 1 : Determine the number of moles of Cadmium and sulfur </h3>
Assuming the mass of the cadmium sulfide is 100 g
Mass of cadmium is 78 g
Mass of sulfur is 22 g
But;
Moles = Mass ÷ Molar mass
Molar mass of Cadmium = 112.411 g/mol
Moles of Cadmium = 78 g ÷ 112.411 g/mol
= 0.694 moles
= 0.69 moles
Molar mass of sulfur is 32.065 g/mol
Moles of sulfur = 22 g ÷ 32.065 g/mol
= 0.686 moles
= 0.69 moles
<h3>Step 3: Determine the whole number mole ratio of Cadmium to sulfur</h3>
Cadmium : Sulfur
Cd : S
0.69 moles : 0.69 moles
0.69/0.69 : 0.69/0.69
1 : 1
Therefore, the empirical formula of greenockite is CdS
Shows the lowest whole number ratio of ions In an ionic compound
Exothermic releases energy(heat) from the system to the surrounding
endothermic takes energy (heat) from the surrounding to the system
Answer:
Gjvb
Explanation:
Using the combined gas law equation as follows:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (kPa)
P2 = final pressure (kPa)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to this question;
T1 = 300K
T2 = -73 + 273 = 200K
P1 = 303kPa
P2 = 202kPa
V1 = 2L
V2 = ?
Using the above formula:
303 × 2/300 = 202 × V2/200
606/300 = 202V2/200
Cross multiply;
606 × 200 = 300 × 202V2
121200 = 60600V2
V2 = 121200/60600
V2 = 2L
The new volume is 2L
