Answer:
156 g
Explanation:
Let's consider the following reaction.
2 NaN₃(s) → 2 Na(s) + 3 N₂
(g)
We can find the moles of N₂ using the ideal gas equation.
P × V = n × R × T
1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K
n = 3.60 mol
The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:
3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃
The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:
2.40 mol × 65.01 g/mol = 156 g
<span>They absorb calcium ions and bicarbonate (hydrogen carbonate) ions.
Sooo B
I hope this helps! :)
</span>
Answer:
Explanation:
The question is not completely clear because some missing parts or grammar (syntax) errors.
Interpreting it, the question is <em>what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.</em>
To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:

That equation works with absolute temperatures, i.e. Kelvin.
- 32ºC = 32 + 273.15 K = 305.15K
Then solve for T₂, substitute and compute:


It has 4 valence electron, all of which are needed to bond with nearest neighbors