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Nat2105 [25]
3 years ago
5

A hockey puck is given an initial speed of 35 m/s on a frozen pond. The puck remains on the ice and slides 132 m before coming t

o rest. The acceleration of gravity is 9.8 m/s 2 . What is the coefficient of friction between the puck and the ice?
Physics
1 answer:
FinnZ [79.3K]3 years ago
7 0
Using kinematic equation,
v²-u²=2as
v = final velocity = 0. since the puck comes to at rest
u = initial velocity = 35 m/s a = acceleration, s = distance traveled = 132 m
Plug all these values in above equation to get a,

0-35² = -2a(132)
35² = 2a(132)
a = 4.64 m/s² 

Net force acting on the puck is,
f = frictional force = μmg 
μ=coefficient of friction
According to Newton's 2nd law of motion,
f=ma
μmg = ma
μ=a/g = 4.64/9.8 = 0.473
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Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st
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Answer:

The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

Explanation:

Given that,

Initial temperature = 0.00°C

Resistance = 75.0 Ω

Final temperature = 525°C

Resistance = 275 Ω

We need to calculate the temperature coefficient of resistivity for a linear thermistor

Using formula for a linear thermistor

R=R_{0}(1+\alpha\Delta T)

R=R_{0}+R_{0}\alpha\Delta T

\alpha=\dfrac{R-R_{0}}{R_{0}\Delta T}

Put the value into the formula

\alpha=\dfrac{275-75}{275\times(525-0)}

\alpha=1.38\times10^{-3}^{\circ}C^{-1}

Hence, The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

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3 years ago
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What is the relationship between the center of gravity and the support base for an object that is in stable equilibrium?
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Answer:

when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium

Explanation:

The concept of center of gravity is equivalent to the concept of center of mass, in this place all external forces applied can be considered.

When we analyze the balance of a body that is the torque it is the one that defines the balance

      τ = F xd

If the torque tends to restore the body to the initial position the balance is stable, but if the torque has to increase the body's rotation the balance is unstable

. When the body tends to rotate the torque with respect to the pivot point at the base it decreases because the distance from the center of gravity to the end of the base decreases in value, but it has to return it to the initial position, the balance is stable. The critical point of this process is when the center of gravity is at the limit of the body base area in this case the torque is zero; If the body rotates a little more the center of gravity is outside the base, the torque changes sign and has to increase the turn, going to an unstable balance.

In summary, when the center of gravity is within the washing area, the torque returns in the body to its initial position and is in a stable equilibrium.

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Answer:

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