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baherus [9]
3 years ago
10

A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes t

he signs set for the initial position, initial velocity and the acceleration ?​
Physics
1 answer:
xeze [42]3 years ago
3 0

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You might be interested in
A 12.0-g bullet is fired horizontally into a 104-g wooden block that is initially at rest on a frictionless horizontal surface a
kobusy [5.1K]

Answer:

 v₀ = 292.3 m / s

Explanation:

Let's analyze the situation, on the one hand we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy, as the data they give us are Let's start with this second part.

We write the mechanical energy when the shock has passed the bodies

    Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

    Em_{f} = K_{e} = ½ k x²

    Em₀ = Em_{f}

    ½ (m + M) v² = ½ k x²

Let's calculate the system speed

    v = √ [k x² / (m + M)]

    v = √[154 0.83² / (0.012 +0.104) ]

    v = 30.24 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

    p₀ = m v₀

After the crash

   p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

   p₀ =  p_{f}

   m v₀ = (m + M) v

   v₀ = v (m + M) / m

let's calculate

   v₀ = 30.24 (0.012 +0.104) /0.012

   v₀ = 292.3 m / s

3 0
3 years ago
Suppose a car approaches a hill and has an initial speed of 108 km/h at the bottom of the hill. The driver takes her foot off of
Aleks04 [339]

Answer:

a) The car will reach a height of 45.9 m.

b) The amount of thermal energy generated is 173382 J.

c) The magnitude of the force of friction is 417.8 N.  

Explanation:

Hi there!

a) In this problem, we have to use the conservation of energy. The energy conservation theorem states that the energy of a system remains constant. Energy can´t be created nor destroyed, only transformed. In the case of the car, the initial kinetic energy is transformed into potential energy as the car´s height increases while coasting up the hill.

Then, all the initial kinetic energy (KE) will be transformed into potential energy (PE) (only if there is no friction).

The equation of KE is the following:

KE = 1/2 · m · v²

Where:

m = mass of the car.

v = speed of the car.

The equation of PE is the following:

PE = m · g · h

Where:

m = mass of the car.

g = acceleration due to gravity.

h = height at which the car is located.

Since work done by friction is negligible, we can assume that all the initial kinetic energy will be transformed into potential energy. Then:

KE at the bottom of the hill = PE at the top of the hill

1/2 · m · v² = m · g · h

Solving for h:

1/2 · v² / g = h

Let´s convert the speed unit into m/s:

108 km/h · 1000 m/ 1 km · 1 h / 3600 s = 30 m/s

Now, let´s calculate h:

h = 1/2 · (30 m/s)² / 9.8 m/s²

h = 45.9 m

The car will reach a height of 45.9 m.

b) In this case, all the kinetic energy is not transformed into potential energy because some energy is transformed into thermal energy due to friction. The thermal energy generated is equal to the work done by friction. Then:

KE at the bottom of the hill = PE + work done by friction

KE = PE + Wfr  (where Wfr is the work done by friction).

1/2 · m · v² = m · g · h + Wfr

1/2 · m · v² - m · g · h = Wfr

1/2 · 710 kg · (30 m/s)² - 710 kg · 9.8 m/s² · 21 m = Wfr

Wfr = 173382 J

The amount of thermal energy generated is 173382 J.

c) The work done by friction is calculated as follows:

Wfr = Ffr · Δx

Where:

Ffr = friction force.

Δx = traveled distance

Please, see the attached figure to notice that the traveled distance can be calculated by trigonometry using this trigonometric rule of right triangles:

sin angle = opposite side / hypotenuse

In our case:

sin 2.9° = h / Δx

Δx = h / sin 2.9°

Δx = 21 m / sin 2.9° = 415 m

Then, solving for the friction force using the equation of the work done by friction:

Wfr = Ffr · Δx

Wfr / Δx = Ffr

173382 J / 415 m = Ffr

Ffr = 417.8 N

The magnitude of the force of friction is 417.8 N

6 0
3 years ago
Calculate the volume of 10g of helium ( M= 4kg/kmol) at 25C and 600 mmHg
Pachacha [2.7K]

Answer:

T=273+25=298 K

n= m/M = 10/ 4 = 2.5

R=0.08206 L.atm /mol/k

760mmHg = 1 atm therefore

600mmHg = X atm

760 X = 600mmHg

X = 600/760 = 0.789 atm

P = 0.789 atm

V= ?

PV= nRT

0.789 V = 2.5 × 0.08206 × 298

V= 2.5 × 0.08206 ×298 / 0.789

V= 77.48 L

I hope I helped you ^_^

8 0
3 years ago
The table lists information about four devices. A 4 column table with 4 rows. The first column is labeled device with entries W,
Anestetic [448]

Answer:

X, Y, Z, W

Explanation:

W has a current of 0 so it has no magnetic field.

X has the most loops (besides W) and the most current so it is the strongest.

Y and Z are the same except Y has more loops so it is stronger than Z.

Also just took the quiz

4 0
3 years ago
Read 2 more answers
A water balloon launcher uses an elastic band with a spring constant of 115 N/m. To use the launcher, you stretch the band back
Lorico [155]

Here elastic balloon launcher will behave like an ideal spring

so here we have

spring constant k = 115 N/m

mass of balloon = 1.3 kg

Part a)

Stretch in the band is given as

x = 0.8 m

now the force on the balloon is given by

F = k x

now from above

F = (115) (0.8) = 92 N

so it will exert 92 N force on it

Part b)

Elastic potential energy is given as

U = \frac{1}{2}kx^2

so here we have

U = \frac{1}{2}(115)(0.8)^2

U = 36.8 J

Part c)

Here in this case we can say that kinetic energy gained by the balloon must be same as the elastic potential energy stored in the rubber because there is no energy loss in this system

So kinetic energy = 36.8 J

Part d)

As we know by the formula of kinetic energy

K = \frac{1}{2}mv^2

36.8 = \frac{1}{2}(1.3)v^2

v = 7.52 m/s

so speed of the balloon will be 7.52 m/s

7 0
3 years ago
Read 2 more answers
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