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andreev551 [17]
3 years ago
6

Which non-metal below is most reactive? (2 points)

Chemistry
2 answers:
ioda3 years ago
5 0
Answer A

Chlorine is usually prepared by electrolysis of molten NaCl or by electrolysis of brine.

hope this helps
Nastasia [14]3 years ago
3 0

The answer is: a. chlorine (Cl).

Chlorine is halogen element.

Halogen elements are in group 17: fluorine (F), chlorine (Cl), bromine (Br) and iodine (I). They are very reactive and easily form many compounds.

They have high electronegativity because they have seven valence electrons in their outermost energy level, so they can gain an electron to have the octet rule.  

Chlorine has atomic number 17, it means it has 17 protons and 17 electrons.

Electron configuration of chlorine atom: ₁₇Cl 1s² 2s² 2p⁶ 3s² 3p⁵.

Chloride is negative ion of chlorine. Chloride is formed when chlorine gain one lectron.

Chloride anion has 17 protons and 18 electrons (like argon-noble gas).

The electron configuration for the chloride ion: ₁₇Cl⁻ 1s²2s²2p⁶3s²3p⁶.


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Answer : The mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

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In V_2O_5, there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of V_2O_5.

As, 2\times 6.022\times 10^{23} number of vanadium atom present in 1 moles of V_2O_5

So, 1.0\times 10^{6} number of vanadium atom present in \frac{1.0\times 10^{6}}{2\times 6.022\times 10^{23}}=8.3\times 10^{-19} moles of V_2O_5

Now we have to determine the mass of V_2O_5.

\text{Mass of }V_2O_5=\text{Moles of }V_2O_5\times \text{Molar mass of }V_2O_5

\text{Mass of }V_2O_5=(8.3\times 10^{-19}mole)\times (181.88g/mole)=1.51\times 10^{-16}g

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