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Naddik [55]
3 years ago
8

What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?

Chemistry
2 answers:
Yuliya22 [10]3 years ago
8 0

Answer:

3.0

Explanation:

const2013 [10]3 years ago
5 0

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

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The high electrical conductivity of metals is primarily due to
zubka84 [21]

High conductivity of metals is caused by electrons that are free to move through the lattice.

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7 0
2 years ago
How many grams of Fe2+ are there in 0.003109 moles of Fe2+?
Sergio [31]

Answer: 0.174 g

Explanation:

First of all understand that charge on an atom like here 2+ will not vary molar mass. because ions are formed by loss or gain of electrons and electrons do not contribute to the mass of an atom or ion. so losing or gaining electron doesnt create any difference.

molar mass of Fe, i.e. mass of 1 mole of Fe is 56 g. So, mass of 1 mole of Fe2+ will also be 56 g.

given is 0.003109 moles of Fe2+,

Use maths,

1 mole of Fe2+ weighs 56 g

So, 0.003109 moles will weigh = (56 g / 1 mol ) x 0.003109 = 0.174 g.

7 0
2 years ago
1. Lab Investigator: Chemical Reactions cannot be used for
Elina [12.6K]

1: viewing any chemical reaction in a laboratory

2: dangerous to look at when it burns & used in photography, fireworks, and flares

3: the product

3 0
3 years ago
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Which statement supports one of Dalton's contributions to the atomic theory?
Mnenie [13.5K]
<span>C) The element nitrogen is made up of carbon and nitrogen</span>
6 0
3 years ago
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Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight
yawa3891 [41]

Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

Amount left for 15.0 years = 3.02 g

Final amount = ?

Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y =  ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

3.02 g/ A = e⁰°⁸⁴³⁹

3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

8 0
3 years ago
Read 2 more answers
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