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Naddik [55]
3 years ago
8

What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?

Chemistry
2 answers:
Yuliya22 [10]3 years ago
8 0

Answer:

3.0

Explanation:

const2013 [10]3 years ago
5 0

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

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How do you find the metal “M”
Elodia [21]

M = Sr (strontium)

<em>Step 1.</em> Calculate the <em>moles of CO_2</em>.

Moles of CO_2 = 0.395 g CO_2 × (1 mol CO_2/44.01 g CO_2)

= 0.008 975 mol CO_2

<em>Step 2</em>. Calculate the <em>moles of MCO_3</em>.

Moles of MCO_3 = 0.008 975 mol CO_2 × (1 mol MCO_3/1 mol CO_2)

= 0.008 975 mol MCO_3

<em>Step 3</em>. Calculate the molar mass of <em>MCO_3</em>

MM = grams/moles = 1.324 g/0.008 75 mol = 147.5 g/mol

<em>Step 4</em>. Calculate the <em>atomic mass of M</em>

M_r = <em>x</em> + 12.01 + 3×16.00 = <em>x</em> + 60.01 = 147.5

<em>x</em> = 147.5 – 60.01 = 87.5

<em>Step 5. Identify M</em>.

The element with the closest atomic mass is Sr (A_r = 87.6).

∴ M = Sr and the compound is SrCO_3.

5 0
4 years ago
A bottle of wine contains 12.8% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm. Calculate the concentratic etha
Scrat [10]

Answer : The mass percent of ethanol is, 10.38 % and the molality of ethanol is, 2.52 mole/kg

Explanation :

In wine, the solute and solvent are ethanol and water respectively.

Given :

12.8 % ethanol by volume means 12.8 mL ethanol present in 100 mL solution.

Volume of ethanol = 12.8 mL

Volume of solution = 100 mL

Volume of water = 100 - 12.8 = 87.2 mL

Density of ethanol = 0.789g/cm^3=0.789g/mL

Density of water = 1 g/mL

Now we have to calculate the mass of ethanol and water.

\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 12.8mL=10.1g

and,

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/mL\times 87.2mL=87.2g

Now we have to calculate the total mass of 100 mL of wine.

Total mass of 100 mL of wine = 10.1 + 87.2 = 97.3 g

Now we have to calculate the mass percent of ethanol.

\text{Mass of percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Total mass of solution}}\times 100

\text{Mass of percent of ethanol}=\frac{10.1g}{97.3g}\times 100=10.38\%

The mass percent of ethanol is, 10.38 %

Now we have to calculate the molality.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

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Molality=\frac{10.1g\times 1000}{46g/mole\times 87.2g}=2.52mole/kg

The molality of ethanol is, 2.52 mole/kg

6 0
4 years ago
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Answer : I hope this helps !

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3 years ago
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