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Rainbow [258]
3 years ago
14

In a controlled experiment, a scientist is studying how long it takes parachutes of different sizes to fall to the ground. What

is the experimental variable?
Chemistry
1 answer:
Elena L [17]3 years ago
4 0
  • The controlled variable would be the weight and time it'll take for the parachutes to land.
  • The uncontrolled variable is the wind and the amount of resistance.

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In the ionic compounds, how is the name of the cation related to the name of the metal?​
lara [203]

Answer:

I don't know if this right or wrong but i think it is predecessor

Explanation:

maybe that is right

4 0
3 years ago
If all of the above images represents the same material, which has the highest temperature?
aleksklad [387]

Answer:

hiii

Explanation:

3 0
4 years ago
According to Le Chatelier's principle, what happens to the equilibrium constant (K) when the concentration of the reactants is d
slavikrds [6]

Answer:

The value of the equilibrium constant (K) remains the same.

Explanation:

A state of dynamic equilibrium is said to have been achieved in a reaction system when the rate of forward reaction equals the rate of reverse reaction.

At equilibrium, doubling the initial concentration of reactants have no effect on the equilibrium constant K. The equilibrium will rather shift to the left or right as required in order to annul the constraint.

5 0
3 years ago
Read 2 more answers
Suppose 0.708g of copper(II) acetate is dissolved in 50.mL of a 46.0mM aqueous solution of sodium chromate.
lisabon 2012 [21]

Answer:

The final molarity of acetate anion in the solution is 0.0046 moles

Explanation:

The balanced equation is

Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)

Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)

Mass of copper (II) acetate present = 0.708 g

Volume of aqueous sodium present = 50 mL

Molarity of sodium chromate = 46.0 mM

Therefore

Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M

Number of moles of copper (II) acetate present = 181.63 g/mol

number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles

Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)

also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)

Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed

7 0
3 years ago
Each of the following is a sign of economic freedom EXCEPT:
MAVERICK [17]

Answer:

b

Explanation:

7 0
3 years ago
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