Answer:
Step-by-step explanation:
Discussion.
Not directly. But the quadratic formula can do it. But that's not your question.
the factors you get must contain the factors for 1 which are 1 and - 1
These factors must add to - 5. There's no way that will happen with 1 and - 1 and you would be creative math if you tried to say that you could make one of the factors (x -1-1-1-1-1-1). That creates a whole new question.
Answer:Ramiro’s method is
Step-by-step explanation:
Did the assignment
Answer:
7/12
Step-by-step explanation:
7+5=12
12-5=7
7/12
Which sequence below represents an exponential sequence A.) {2,6,10,14,18,...} B.) {3,5,9,16,24,...} C.) {4,8,24,96,...} D.) {25
denis-greek [22]
Answer:
D.) {256,64,16,4,...}
Step-by-step explanation:
Look for the sequence in which adjacent terms are related by a common ratio.
A. 10/6 ≠ 6/2
B. 9/5 ≠ 5/3
C. 8/4 ≠ 24/8
D. 64/256 = 16/64 = 4/16 = 1/4 . . . . this exponential sequence has a common ratio of 1/4
<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
