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salantis [7]
4 years ago
14

Count the dots to make sure that all of the valence electrons are represented 2

Physics
1 answer:
Semenov [28]4 years ago
5 0

Do you have a diagram or anything?

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2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg
Yakvenalex [24]

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s

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3 years ago
Box A has a mass of 35.0kg and Box B has a mass of 20.0kg. What is the tension on
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Who wants to do my missing physics work
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3 years ago
A 325-g model boat facing east floats on a pond. The wind in its sail provides a force of 1.85 N that points 25° north of east.
podryga [215]

Answer:

Vf = 4.40  m/s  and  θ = 88º

Explanation:

To solve this problem, let's look for the resultants of the force and with this we calculate the accelerations in each axis.

Let's use trigonometry to break down the forces

     Sin 25 = F1x / F1

     Cos 25 = F1y / F1

     Fix = F1 sin 25

     F1x = 1.85 sin 25

     F1x = 0.78 N

     F1y = 1.85 cos 25

     F1y = 1.67 N

     F2 = - 0.782 N j ^  (south)

     F3 = - 0.750 N i ^    (west)

We write Newton's second law

X axis (East-West)

     F1x - F3 = m ax

     ax = (F1x - F3) / m

     ax = (0.78 - (0.750)) / 0.325

     ax = 0.092 m / s²

Y axis (North-South)

     F1y - F2 = m ay

     ay = (1.67- (0.782)) / 0.325

     ay = 2.73 m / s²

Let's calculate the magnitude and direction of the acceleration

     a = RA ax2 + ay2

     a = RA 0.092² + 2.73²

     a =  2.73m / s²

     tan θ = ay / ax

     θ = tan⁻¹ (2.73/0.092)

     θ = tan⁻¹ 29.67

     θ = 88º

We calculate the speed, notice that we use the total acceleration to be able to use the totol displacement

Vf² = vo² + 2 at D

Vf² = 0 + 2 2.73 3.55

Vf = √ 19.38

Vf = 4.40  m / s

θ = 88º

8 0
3 years ago
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