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Kitty [74]
3 years ago
9

2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg

baseball travel in order for its kinetic energy to equal this internal energy?
Physics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s

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yes because your mass doesn't change but your weight can


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3 years ago
A ball is dropped from a height of 20 meters. At what height does the ball have a velocity of 10 meters/second?
borishaifa [10]

Answer:B

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Using v*v=u*u+2gs

v*v=0+2*9.8*20

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6 0
3 years ago
Earth rotates on its axis once every 24 hours, so that objects on its surface execute uniform circular motion about the axis wit
cestrela7 [59]

Answer:

v=1667.9km/h

a_{cp}=436.6km/h^2

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The speed is the distance traveled divided by the time taken. The distance traveled in 24hs while standing on the equator is the circumference of the Earth C=2\pi R, where R=6371km is the radius of the Earth.

We have then:

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And then we use the centripetal acceleration formula:

a_{cp}=\frac{v^2}{R}=\frac{(1667.9km/h)^2}{(6371km)}=436.6km/h^2

6 0
3 years ago
A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface a
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The speed would be in a decimal? Or do you want it in a fraction?
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