Question

2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

Answer 1

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s