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2 years ago

Who wants to do my missing physics work

Physics

1 answer:

kotegsom [21]2 years ago

4 0

Answer:

<h2>WHAT IF I HATE PHYSICS ?</h2>

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Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to th

Sergeu [11.5K]

Answer:

here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa

Explanation:

As wee know that the amplitude of the wave will decide the energy of the wave

Here we know that energy density of electromagnetic wave is given as

$u = \frac{1}{2}\epsilon_0E_0^2$

now we have

$\frac{I}{c} = \frac{1}{2}\epsilon_0 E_0^2$

so here we can say that intensity of the wave at the given distance from the source is given by formula

$I = \frac{P}{4\pi r^2}$

so here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa.

5 0

3 years ago

Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of LaTe

RideAnS [48]

Answer:

5.5x 10^-11 C

Explanation:

Pls see attached file

7 0

3 years ago

Difference between derived quantity and physical quantity

Lerok [7]

Answer:

<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>

<h3>Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other quantities. </h3>

Explanation:

#Let's Study

#I Hope It's Helps

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6 0

2 years ago

Gli iceberg nel Nord Atlantico rappresentano un rischio per la navigazione, costringendo ad allungare le rotte di navigazione di

nikklg [1K]

I DONT UNDERSTND IS ANOTHER LANGUAGR

6 0

3 years ago

Transmission Lines and Health. Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the elec

Blababa [14]

Calculate the magnetic field strength at the ground. Treat the transmission line as infinitely long. The magnetic field strength is then given by:

B = μ₀I/(2πr)

B = magnetic field strength, μ₀ = magnetic constant, I = current, r = distance from line

Given values:

μ₀ = 4π×10⁻⁷H/m, I = 170A, r = 8.0m

Plug in and solve for B:

B = 4π×10⁻⁷(170)/(2π(8.0))

B = 4.25×10⁻⁶T

The earth's magnetic field strength is 0.50G or 5.0×10⁻⁵T. Calculate the ratio of the line's magnetic field strength to earth's magnetic field strength:

4.25×10⁻⁶/(5.0×10⁻⁵)

= 0.085

= 8.5%

The transmission line's magnetic field strength is 8.5% of that of earth's natural magnetic field. This is no cause for worry.

8 0

3 years ago