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Igoryamba
3 years ago
10

The end point of a titration was reached after 22 ml of 0.050 m disodium edta titrant was dispensed into a solution containing t

he zinc ion. calculate the moles of disodium edta used
Chemistry
2 answers:
ale4655 [162]3 years ago
4 0
The moles  of disodium edta  used is  calculated  using  the  below  formula


moles =molarity  x  volume in  liters

molarity=0.050m
volume  in  liters = 22/1000=0.022 L

moles  is  therefore=  0.022 x0.050  =1.1  x10^-3  moles  of  disodium  edta


Dimas [21]3 years ago
3 0

Answer:

moles =molarity  x  volume in  liters

molarity=0.050m

volume  in  liters = 22/1000=0.022 L

moles  is  therefore=  0.022 x0.050  =1.1  x10^-3  moles  of  disodium  edta

Explanation:

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In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

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By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

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3 years ago
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2 years ago
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When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is CH_{3}C(CH_{3})_{2}CHClCH_{3} (3-chloro-2,2-dimethylbutane), ClCH_{2}C(CH_{3})_{2}CH_{2}CH_{3} (1-chloro-2,2-dimethylbutane) and ClCH_{2}CH_{2}C(CH_{3})_{2}CH_{3} (1-chloro-3,3-dimethylbutane).

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3 years ago
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