Explanation:
The given data is as follows.
Density of vinegar = 1.0 g/ml
Specific heat capacity = 4.25 
= 
, and 
= 
Relation between enthalpy and specific heat is as follows.
Hence, putting the values into the above formula as follows.
= 
(as density = 
)
= - 315 J
Thus, we can conclude that the enthalpy of reaction is -315 J.
As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.
For your first question, that equation only works if your situation is occurring at a constant temperature. Your original question is such a situation - everything occurs at 298.15 K. Therefore, you can use this value in the equation to calculate work.
For your second question, Charles' Law describes how the volume of gas changes as you heat or cool it, PROVIDED PRESSURE AND MOLES OF GAS REMAIN CONSTANT THE WHOLE TIME. In your original question above, temperature stays constant while volume changes. However, what they don't tell you is that this necessarily requires a change in either pressure or moles of gas. Because the question works with the same sample the of gas the whole time (i.e. moles are constant), it is pressure that is changing (and this change will occur according to Boyle's Law, since temperature and moles are held constant).
Hope that clarifies things!
Answer:
0.3936 J/gC
Explanation:
using the formula: q=mcΔt
q= 7032J
m=812g
ΔT = 22C
plug in and solve:
7032=(812)(c)(22)
c=7032/(812)(22)
c=0.39 J/gC
Answer:
Explanation:
There are two main types of ocean currents: currents driven mainly by wind and currents mainly driven by density differences. Density depends on temperature and salinity of the water. Cold and salty water is dense and will sink. Warm and less salty water will float.
Answer:
25000 ppm
Explanation:
<em>Parts Per Million </em>is defined as the number of parts of a solute per one million parts of a solution.
ppm = (Weight of Solute / Weight of Solution) × 10⁶ ---(1)
Let us suppose that the air (solution) weights 100 grams, then 2.5 % of water vapors will have following mass,
Mass of Vapors g / 100 g × 100 = 2.5
Or,
Mass of Vapors = 2.5 × 100 / 100
Mass of Vapors = 2.5 g
Hence, mass of water vapors is 2.5 g.
Now, putting mass of water vapors and air in eq. 1,
ppm = (2.5 / 100) × 10⁶
ppm = 25000
