Question

I

Answer 1

Answer:

The new force between charges is 2 N.

Explanation:

It is given that, a 3 C charge and a 6 C charge feel 4 N of force between them.

The force between charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

r is distance between charges

Original force is :

$4=\dfrac{k(3)(6)}{r^2}\ ....(1)$

If the 6 C is replaced  with a 3 C, new force between them is given by :

$F'=\dfrac{k(3)(3)}{r^2}\ ....(2)$

Dividing equation (1) and (2) we get :

$\dfrac{4}{F'}=\dfrac{2}{1}\\\\F'=2\ N$

So, the new force between charges is 2 N.