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Rina8888 [55]
4 years ago
6

A uterine ultrasound is performed in the hospital outpatient department and interpreted and reported by a contracted radiologist

. What modifier is used for the services of the radiologist?
Physics
1 answer:
KiRa [710]4 years ago
4 0

Answer:

Explanation:

It is pertinent to note that modifier 26 is appropriate when the physician supervised or interprets a diagnostic test, even if he or she did not perform the test personally. Also do not append modifier 26 if there is a code to describe only the professional/physician component of a given service (examples are 93010 Electrocardiogram, routine ECG with at least 12 leads, interpretation and report only).

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A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9
Black_prince [1.1K]

Answer:

C = 46.891 \mu F

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

s = \frac{P}{P.F} < COS^{-1} 0.65

S = \frac{1250}{0.65} < 49.45

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]

solving for Q_{new}

Q_{new} = P tan [cos^{-1} P.F new]

Q_{new} = 1250 [tan[cos^{-1}0.9]]

Q_{new} = 605.40 VARS

Q_C = Q - Q_{new}

Q_C = 1461 - 605.4 = 855.6 vars

Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C

C = \frac{Q_C}{ v_{rms}^2 \omega}

C = \frac{855.6}{220^2 \times 2\pi \times 60}

C = 4..689 \times 10^{-5} Faraday

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6 0
4 years ago
A body is projected vertically upwards with a velocity of 10m/s from a vertically upward position at height h another body is dr
RoseWind [281]

Answer:

0.25 second  

Explanation:

Given :

Velocity, v = 10 m/s

The height,

$ h = \frac{v^2}{2g} $

$ h = \frac{10^2}{2\times 9.8} $

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Therefore the time at which both the bodies meet is

$ t = \frac{h}{v+v} $

$ t = \frac{5}{10+10} $

$ t = \frac{5}{20}  = 0.25$

So, time taken is 0.25 seconds

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wlad13 [49]

Answer:

temperature and red

is the answer

Explanation:

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