Acceleration of gravity is proportional to 1/D² .
('D' is the distance from the Earth's center.)
We need (D / R)² = 9.8
('R' is the Earth's radius.)
D/R = √9.8 = 3.13
Distance from Earth's <u>center</u> = 3.13 R
Distance above Earth's <u>surface</u> = 2.13 R = about 13,570 km =====================================================
<span>Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)
Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)</span><span>
D / R = √9.8 = 3,13
Distanța de la <u>centrul</u> Pamantului = 3,13 R
Distanța de deasupra <u>suprafetei</u> Pamantului = 2.13 R = aproximativ <span><em>13,570 km</em></span></span>
Answer:
runway use is 3307.8 feet
Explanation:
given data
velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s
time = 28 seconds
weight = 28000 lbs
to find out
How many feet of runway was used
solution
we will use here first equation of motion for find acceleration
v = u + at ..............1
here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time
put here value in equation 1
72.016 = 0 + a(28)
a = 2.572 m/s²
and
now apply third equation of motion
s = ut + 0.5×a×t² .......................2
here s is distance and u is initial speed and t is time and a is acceleration
put here all value in equation 2
s = 0 + 0.5×2.572×28²
s = 1008.24 m = 3307.8 ft
so runway use is 3307.8 feet
Answer:
3
Explanation:
The solution is in the attached files below
Answer:increases
Explanation:
If we are going upward in an elevator from the ground floor to the top floor then it indicates that your distance from the center of the earth is increasing while the time period remains the same.
If the radial distance is increased then the tangential velocity of the object must be increased because the time period is the same.
This can be best explained by taking an example of a car moving in a circle of radius r. If radial is increased for the same period then the car has to travel at a higher velocity to make in time.
Two components (vertical and horizontal)
