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4 years ago

If two objects with static charge are attracted what do you know about them?

Physics

1 answer:

klemol [59]4 years ago

4 0

They carry opposite charge ( one has negative charge and one has positive charge)

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*photo attached* The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.67 m and 1.01 m, respectivel

stiks02 [169]

(a) The speeds of the tips of both rotors; main rotor <u>178.3 m/s</u> and tail rotor <u>218.4 m/s</u>.

(b) The speed of the main rotor is <u>0.52</u> speed of sound, and the speed of the tail rotor is <u>0.64</u> speed of sound.

<h3>Linear speed of main motor and tail rotor</h3>

v = ωr

where;

ω is the angular speed (rad/s)
r is radius (m)

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

v(tail rotor) = 218.4 m/s

<h3>Speed of the rotors with respect to speed of sound</h3>

% speed (main motor) = 178.3/343 = 0.52 = 52 %

% speed (tail motor) = 218.4/343 = 0.64 = 64 %

Thus, the speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

Learn more about linear speed here: brainly.com/question/15154527

#SPJ1

5 0

2 years ago

How do defy gravity?

kaheart [24]

Exert force upward.
Like when you pick something up from the floor, or walk up the stairs.

6 0

4 years ago

For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas

nirvana33 [79]

Explanation:

The force of the roller-coaster track on the cart at the bottom is given by :

$F=\dfrac{mv^2}{R}$ , m is mass of roller coaster

Case 1.

R = 60 m v = 16 m/s

$F=\dfrac{(16)^2m}{60}=4.26m\ N$

Case 2.

R = 15 m v = 8 m/s

$F=\dfrac{(8)^2m}{15}=4.26m\ N$

Case 3.

R = 30 m v = 4 m/s

$F=\dfrac{(4)^2m}{30}=0.54m\ N$

Case 4.

R = 45 m v = 4 m/s

$F=\dfrac{(4)^2m}{45}=0.36m\ N$

Case 5.

R = 30 m v = 16 m/s

$F=\dfrac{(16)^2m}{30}=8.54m\ N$

Case 6.

R = 15 m v =12 m/s

$F=\dfrac{(12)^2m}{15}=9.6m\ N$

Ranking from largest to smallest is given by :

F>E>A=B>C>D

5 0

3 years ago

Introduction Team Problem 2 You jump into the deep end of Legion Pool and swim to the bottom with a pressure gauge. The gauge at

Kaylis [27]

Answer:

Depth of the pool, h = 4.004 cm

Explanation:

Pressure at the bottom, P = 39240 N/m²

The density of water, d = 1000 kg/m³

The pressure at the bottom is given by :

P = dgh

We need to find the depth of pool. Let h is the depth of the pool. So,

$h=\dfrac{P}{dg}$

$h=\dfrac{39240\ N/m^2}{1000\ kg/m^3\times 9.8\ m/s^2}$

h = 4.004 m

So, the pool is 4.004 meters pool. Hence, this is the required solution.

5 0

4 years ago

47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a

butalik [34]

Answer:

kinetic

Explanation:

kinetic energy is powered by motion or gravity the steeper the hill is the faster a ball will roll

7 0

3 years ago