Given the relationship: v = wavelength times frequency
this should be as simple as multiplying it out :)
for any other variable just rearrange
velocity = lambda x frequency
where lambda is the wavelength
units:
m/s = m x Hz (1/s)
Answer:
Air.
Explanation:
To know which option is correct, let us consider the relationship between velocity and the wavelength of a wave. This is illustrated below:
Velocity, wavelength and frequency are related by the following equation:
Velocity = wavelength × frequency
v = λf
From the equation above, we can see clearly that the velocity is directly proportional to the wavelength.
This means that an increase in the wavelength will lead to an increase in the velocity and also, a decrease in the wavelength will lead to a decrease in the velocity.
Now, considering the table given in the question above, we can see that the wave has a higher speed in air. This simply means that the wave will also have a higher wavelength in air.
Thus, the correct answer to the question is: air
Answer:
a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Explanation:
a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:
Jet
(1)
Glider
(2)
Where:
- Thrust of jet engines, measured in newtons.
- Tension in the cable connecting the jet and glider, measured in newtons.
, 
- Masses of the glider and the jet, measured in kilograms.
- Acceleration of the glider-jet system, measured in meters per square second.
If we know that 
, 
and 
, then the solution of this system of equations:
By (2):
By (1):
The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Answer:
5 m
Explanation:
Speed of waves is as the product of frequency and wavelength hence expressed as s=fw where f is the frequency of waves in Hz, s is the speed in m/s and w is wavelength in meters.
Making w the subject of the formula then
Substituting 335 m/s for s and 67 Hz for f then the wavelength is
Wavelength is the distance between successive crests. Since the string is 10m, wavelengths of 5m each will be 2 and the crests will be 3.
Wavelenth=5 m
