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3 years ago

Find the velocity of an object dropped from a height of 300 m at the moment it hits the ground?

Physics

1 answer:

Maurinko [17]3 years ago

7 0

G (gravity) = 9.81 M/s/s x = 300m v = Square root of (2 x 9.81 x 300)
V = sq rt of 5886
V = 76.72 m/s

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3 years ago

What is the acceleration of an object that takes 20 sec to change from a speed of 200 m/s to 300 m/s ?

marin [14]

Given:

initial velocity, u = 200 m/s

Final velocity, v = 300 m/s

Time taken, t = 20 sec

To be calculated:

Calculate the acceleration of given object ?

Formula used:

Acceleration = v - u / t

Solution:

We know that,

Acceleration = v - u / t

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4 years ago

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4 years ago

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3 years ago

A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the roc

jenyasd209 [6]

Given:

Speed = 2.70 m

Time, t = 2.10 seconds

Let's solve for the following:

• (a) The horizontal component of the velocity.

To find the horizontal component, apply the formula:

$V_{ox}=V_o\cos \theta$

Where:

Vo is the initial speed = 2.70 m

θ = 0 degrees

Hence, we have:

$\begin{gathered} V_{ox}=2.70\cos 0 \\ \\ V_{ox}=2.7\text{ m/s} \end{gathered}$

The horizontal component of the velocity just before it lands is 2.70 m/s.

• (b) The vertical component of the velocity.

To find the vertical component, apply the formula:

$V_{oy}=V_{0y}-gt=\text{V}_{oy}\text{ sin}\Theta-gt$

Where:

g is the acceleration due to gravity = 9.8 m/s²

t is the time = 2.10 s

Hence, we have:

$\begin{gathered} V_{oy}=V_{oy}\sin \theta-gt \\ \\ V_{oy}=2.70\sin 0-9.8(2.10) \\ \\ V_{oy}=0-20.58 \\ \\ V_{oy}=-20.58\text{ m/s} \end{gathered}$

The vertical component of the velocity just before it lands is -20.58 m/s.

(c) Here, the initial speed is equal to the constant horizontal speed.

Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.

The initial vertical velocity is 0 m/s in both cases.

Therefore, in part (b) the vertical component will remain constant.

ANSWER:

(a) 2.70 m/s

(b) -20.58

(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.

6 0

1 year ago