My answer to the problem is as follows:
<span>1. Use the kinematic formula
Vf = Vi + a*t
for a, Vi = 3.0 m/s, a = 0.5 m/s/s, and t = 7.o s.
for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s.
I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
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Answer:
8.80 Hz
Explanation:
The frequency of a loaded spring is given by

where k and m are the spring constant and the mass of the load respectively. The values of these do not change because they are internal properties of the components of the system.
Hence, the frequency of the vertical spring mass does not change and is 8.80 Hz.
On the other hand, the frequency of the simple pendulum is affected because it is given by

where g and l are acceleration due to gravity and length of the pendulum, respectively. It is thus seen that it depends on g, which changes with location. In fact, the new frequency is given by
