Answer:
12.17 m/s²
Explanation:
The formula of period of a simple pendulum is given as,
T = 2π√(L/g)........................ Equation 1
Where T = period of the simple pendulum, L = length of the simple pendulum, g = acceleration due to gravity of the planet. π = pie
making g the subject of the equation,
g = 4π²L/T²................... Equation 2
Given: T = 1.8 s, l = 1.00 m
Constant: π = 3.14
Substitute into equation 2
g = (4×3.14²×1)/1.8²
g = 12.17 m/s²
Hence the acceleration due to gravity of the planet = 12.17 m/s²
Use the formula dgh + p atm
d is density g is gravitational field strength h heigh or depth and p atm is atmospheric pressure
1000 x 10 x 20 + 100000 = 300000
almost 300,000 pascal
Answer:
Explanation:
Given
,
,
,
The tension of the spring is
The force in the spring is equal to centripetal force so
But Fc is also
Fc=KxΔr
Replacing
total distance is
I think B is the most correct, because logically it's harder to bend a stiffer spring than it is to bend a softer one. Also, I don't think length comes into play. So B.
