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Tanya [424]
4 years ago
15

Find the standard deviation for the group of data items 4, 4, 4, 4, 6, 8 The standard deviation is (Simplify your answer. Round

to two decimal places as needed.)
Mathematics
1 answer:
marysya [2.9K]4 years ago
5 0

Answer: 1.53

Step-by-step explanation:

The given data : 4, 4, 4, 4, 6, 8

Number of data values : n= 6

The mean value of the given data will be  :-

\overline{x}=\dfrac{\sum_{i=1}^{6}x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{30}{6}=5

The formula to find standard deviation:_

\sqrt{\dfrac{\sum(x-\overline{x})^2}{n}]

Now,

\sum_{i=1}^{6}(x_i-\overline{x})^2=(-1)^2+(-1)^2+(-1)^2+(-1)^2+(1)^2+(3)^2\\\\=1+1+1+1+1+9=14

The standard deviation will be :-

\sigma=\sqrt{\dfrac{14}{6}}\approx1.53

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babymother [125]

Answer:

P≈14.14

Step-by-step explanation:

Diagonal

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3 years ago
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A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and the standard
ser-zykov [4K]

Answer:

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}

Hence, the correct interpretation for the confidence interval is given by option a).

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We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

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Step-by-step explanation:

x = number of glasses sold

She charges $0.50 per glass, so her revenue is

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Answer:

a-2/3b

Step-by-step explanation:

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alisha [4.7K]

\longrightarrow{\blue{  141x  - 8y  }} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

97x + 58y - 66y + 44x

Let us rewrite the expression so that the like terms are next to each other.

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= 141x  - 8y

\sf\pink{Happy\:learning! }

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