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Tanya [424]
3 years ago
15

Find the standard deviation for the group of data items 4, 4, 4, 4, 6, 8 The standard deviation is (Simplify your answer. Round

to two decimal places as needed.)
Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer: 1.53

Step-by-step explanation:

The given data : 4, 4, 4, 4, 6, 8

Number of data values : n= 6

The mean value of the given data will be  :-

\overline{x}=\dfrac{\sum_{i=1}^{6}x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{30}{6}=5

The formula to find standard deviation:_

\sqrt{\dfrac{\sum(x-\overline{x})^2}{n}]

Now,

\sum_{i=1}^{6}(x_i-\overline{x})^2=(-1)^2+(-1)^2+(-1)^2+(-1)^2+(1)^2+(3)^2\\\\=1+1+1+1+1+9=14

The standard deviation will be :-

\sigma=\sqrt{\dfrac{14}{6}}\approx1.53

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The vertex form:

y=a(x-h)^2+k\\\\(h,\ k)-vertex

Use (a+b)^2=a^2+2ab+b^2\qquad(*)


2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2

<h3>Answer: (-3, -2).</h3>

Other method:

f(x)=ax^2+bx+c\\\\vertex:(h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)

We have

f(x)=2x^2+12x+16\\\\a=2,\ b=12,\ c=16

Substitute:

h=\dfrac{-12}{(2)(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+16=2(9)-36+16=18-36+16=-2

<h3>Answer: (-3, -2).</h3>
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<h3>Key points :-</h3>

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✪ The symbol for similarity is ~.

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\large{|\underline{\mathtt{\red{A}\blue{n}\orange{c}\pink{i}\blue{e}\purple{n}\green{t}\red{E}\blue{n}\orange{i}\green{g}\red{m}\purple{a}\pink{29}}}}

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