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Tanya [424]
3 years ago
15

Find the standard deviation for the group of data items 4, 4, 4, 4, 6, 8 The standard deviation is (Simplify your answer. Round

to two decimal places as needed.)
Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer: 1.53

Step-by-step explanation:

The given data : 4, 4, 4, 4, 6, 8

Number of data values : n= 6

The mean value of the given data will be  :-

\overline{x}=\dfrac{\sum_{i=1}^{6}x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{30}{6}=5

The formula to find standard deviation:_

\sqrt{\dfrac{\sum(x-\overline{x})^2}{n}]

Now,

\sum_{i=1}^{6}(x_i-\overline{x})^2=(-1)^2+(-1)^2+(-1)^2+(-1)^2+(1)^2+(3)^2\\\\=1+1+1+1+1+9=14

The standard deviation will be :-

\sigma=\sqrt{\dfrac{14}{6}}\approx1.53

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3 years ago
If 13 = 4.5 -5k what is the value of k
USPshnik [31]

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K = negative 1.7

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Hope this helped

7 0
3 years ago
Greg earned $900 for washing 30windowa last month if Greg’s wage is increased by $2 per window this month how much will he earn
PtichkaEL [24]

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He earned for washing 30 windows this month =  $960.

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3 0
3 years ago
A movie theater charges 8 dollars for adults and 4 dollars for seniors. On a particular day when 353 people paid an admission, t
sammy [17]

A movie theater charges 8 dollars for adults and 4 dollars for seniors. On a particular day when 353 people paid an admission, the total receipts were 1688 dollars. How many who paid were adults? . How many who paid were seniors?

<em><u>Answer:</u></em>

There were 69 adults and 284 seniors

<em><u>Solution:</u></em>

Let "a" be the number of adults

Let "s" be the number of seniors

Cost of 1 adult = $ 8

Cost of 1 senior = $ 4

<em><u>On a particular day when 353 people paid an admission</u></em>

Therefore,

number of adults + number of seniors = 353

a + s = 353

a = 353 - s ---------- eqn 1

<em><u>The total receipts were 1688 dollars</u></em>

Therefore, we frame a equation as:

number of adults x Cost of 1 adult + number of seniors x Cost of 1 senior = 1688

a \times 8 + s \times 4 = 1688

8a + 4s = 1688 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

8(353 - s) + 4s = 1688

2824 -8s + 4s = 1688

4s = 2824 - 1688

4s = 1136

<h3>s = 284</h3>

<em><u>Substitute s = 284 in eqn 1</u></em>

a = 353 - 284

<h3>a = 69</h3>

Thus there were 69 adults and 284 seniors in movie theater

7 0
3 years ago
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