3 years ago

Help me please !!!!!!!!!!!!!!!

Mathematics

1 answer:

Crank3 years ago

3 0

16 units just count the tiny lines in the middle by 2

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Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)

nekit [7.7K]

To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1

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3 years ago

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ay² = 36y² - 121 + b |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

$\boxed{a=\dfrac{36y^2-121+b}{y^2}}$

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Step-by-step explanation:

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