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3 years ago

Brainliest ? For which inequality is (0,0) a solution?

Mathematics

2 answers:

Arada [10]3 years ago

4 0

Answer:

C. y-5>3x-7

Step-by-step explanation:

The point (0, 0) would be a solution because the inequality is greater than or equal to. Since the 2 sides become equal, the inequality is true which means (0, 0) is a solution.

please mark me brainliest :)

xxMikexx [17]3 years ago

3 0

Answer:

C. y-5>3x-7

Step-by-step explanation:

If you multiply y and x to 0 you get -5 > -7

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Simplify the given expression, using only positive

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Answer: x=4 y=14 z=4

Step-by-step explanation:

On edge it is that

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3 years ago

Please help i don't know how to do this

GaryK [48]

Step-by-step explanation:

y = (x - 4)/x = x/x - 4/x = 1 - 4/x

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2 years ago

A tax assessor wants to assess the mean property tax bill for all homeowners in a certain state. From a survey ten years ago, a

Jet001 [13]

Answer:

The answer is below

Step-by-step explanation:

From the table, the mean (μ) = 1390.75 and the standard deviation (σ) = 518.75

The confidence level (C) = 90% = 0.9

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The z score of α/2 (0.05) is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.645.

The margin of error (E) is given as:

$E=Z_\frac{\alpha}{2}*\frac{\sigma}{\sqrt{n} } \\\\E=1.645*\frac{518.75}{\sqrt{14} } =228.07$

The confidence interval = μ ± E = 1390.75 ± 228.07 = (1162.68, 1618.82)

The confidence interval is between 1162.68 and 1618.82.

7 0

3 years ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

2 years ago

Explain how you got the answer(:

Natali [406]

Hey there :) I'm pretty sure that your answer is D) ∠S ≅ <span>∠Y because corresponding angles of similar triangles are congruent.

I think that it is the answer because if you shift your paper around, and look at the angles from different views, you can tell that angles S and Y are congruent, or the same, because of the way that both angles are at the end of the longer sides of both triangles.

So, your answer is D!

~Hope this helped!~</span>

8 0

3 years ago

Read 2 more answers