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Nuetrik [128]
4 years ago
14

Help

Mathematics
2 answers:
enyata [817]4 years ago
5 0
The answer is a hope this helps 
STALIN [3.7K]4 years ago
5 0

answer is b hope this helps :) the other person that answered is just a mean person

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the mean monthly rent for a sample of studio apartments in one city is $1260 with a standard deviation of $230. the monthly rent
il63 [147K]

Answer:

$1743, $1973, $1789 and $685 are unusual data values. $1973 is very unusual data value.

Step-by-step explanation:

The data values will be unusual if the data values more than 2 standard deviations away from mean.

mean=1260

standard deviation=230

mean-2*standard deviation

1260-2*230

800

mean+2*standard deviation

1720

mean±2*standard deviation=(800,1720)

The values that don't lie in this interval will be unusual.

mean-3*standard deviation

1260-3*230

570

mean+3*standard deviation

1260+3*230

1950

mean±3*standard deviation=(570,1950)

The values that don't lie in this interval will be very unusual.

$1099 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1099 is not unusual.

$1651 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1651 is not unusual.

$1743 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1743 is unusual.

$1973 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1973 is unusual. Also,  $1973 don't lie in the interval mean±3*standard deviation and so it is more than the three standard deviation away from mean. So, $1973 is very unusual.

$846 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $846 is not unusual.

$1789 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1789 is unusual.

$1398 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1398 is not unusual.

$685 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $685 is unusual.

5 0
4 years ago
PLZ HURRY will give BRAIN-LY-EST and 20 points if correct
Step2247 [10]

Answer:

{ \boxed{ \tt{4x + 4x \: → \: 8x}}} \\  \\ { \boxed{ \tt{3x + 5x + 8 \:→ \: 8x + 8 }}} \\  \\ { \boxed{ \tt{ - 7x + 4 + 3x \: → \:  - 4x + 4}}} \\  \\ { \boxed{ \tt{4x + 4x + 4x + 4x \: → \: 16x}}}

5 0
3 years ago
Read 2 more answers
A particular rocket taking off from the earth surface uses fuel at a constant rate of 12.5 gallons per minute the rocket initial
faltersainse [42]

Answer:

y=12.5x+225

Step-by-step explanation:

Let

x ----> the number of minutes

y ----> the amount of fuel in gallons

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the unit rate or slope

b is the y-intercept or initial value

we have that

The unit rate or slope is equal to

m=12.5\ \frac{gal}{min}

b=225\ gal ----> initial value (value of y when the value of x is equal to zero)

substitute

y=12.5x+225

3 0
3 years ago
Carl is boarding a plane. He has 2 checked bags of equal weight and a backpack that weighs 4kg. The total weight of Carl's bagga
baherus [9]
Let a checked bag = x
Since they are of the same weight
The two checked bags = x+x=2x
Another backpack that weighs 4kg
Total baggage =35
:- 2x + 4 = 35
2x = 35-4
2x = 31

The two checked bag weighs 31
Therefore the weight of one =15.5kg
8 0
3 years ago
today you are going to Ms. Debbie's house who lives 45 minutes from your house. What time should you leave to get there at 5:00?
Whitepunk [10]

60 minutes in an hour. 60-45=15

4:15

---

hope it helps

(sorry I didn't know how to explain it)

6 0
3 years ago
Read 2 more answers
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