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2 years ago

8

e force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the

charge on particle A is 7.2 × 10-8 coulombs, what is the charge of particle B? (k = 9.0 × 109 newton·meters2/coulomb2)

2 answers:

anastassius [24]2 years ago

7 0

The force acting between the particles is

$F=k \frac{Q_{1}Q_{2}}{r^2}$
Then
$Q_{2}= \frac{5.2 \times 10^-^5 \times 0.024^2}{ 9.0 \times 10^9 7.2 \times 10^-^8} =4.622 \times 10^-^1^1C$

True [87]2 years ago

6 0

Answer:

the answer is b for plato users

Explanation:

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