Question

e force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the charge on particle A is 7.2 × 10-8 coulombs, what is the charge of particle B? (k = 9.0 × 109 newton·meters2/coulomb2)

Answer 1

The force acting between the particles is

$F=k \frac{Q_{1}Q_{2}}{r^2}$
Then
$Q_{2}= \frac{5.2 \times 10^-^5 \times 0.024^2}{ 9.0 \times 10^9 7.2 \times 10^-^8} =4.622 \times 10^-^1^1C$

Answer 2

Answer:

the answer is b for plato users

Explanation: